Questions: Draw the products of the acid-base reaction between the species shown below. Two equivalents of OH- are used in this reaction. OH- Draw the molecules or ions on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars, including charges where needed. The single bond is active by default.

Draw the products of the acid-base reaction between the species shown below. Two equivalents of OH- are used in this reaction.

OH-

Draw the molecules or ions on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars, including charges where needed. The single bond is active by default.

Transcript text: Draw the products of the acid-base reaction between the species shown below. Two equivalents of $\mathrm{OH}^{-}$ are used in this reaction. $\mathrm{OH}^{-}$ Draw the molecules or ions on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars, including charges where needed. The single bond is active by default.

Solution

Solution Steps

Step 1: Identify the acidic protons

The reactant is a carboxylic acid with two acidic protons: one from the carboxylic acid group (-COOH) and one from the alcohol group (-OH). Since two equivalents of hydroxide (OH⁻) are used, both of these protons will react.

Step 2: Deprotonation of the carboxylic acid

The first hydroxide ion will deprotonate the most acidic proton, which is the carboxylic acid proton. This forms a carboxylate anion.

Step 3: Deprotonation of the alcohol

The second hydroxide ion will deprotonate the alcohol proton, forming an alkoxide anion.