Questions: Solve for (x) in the equation below.
Round your answer to the nearest hundredth.
Do not round any intermediate computations.
[2^x+2=6]
[x=]
Transcript text: Solve for $x$ in the equation below.
Round your answer to the nearest hundredth.
Do not round any intermediate computations.
\[
2^{x+2}=6
\]
\[
x=
\]
Solution
Solution Steps
Step 1: Take the Logarithm of Both Sides
We start with the equation:
\[
2^{x+2} = 6
\]
Taking the natural logarithm of both sides gives us:
\[
\ln(2^{x+2}) = \ln(6)
\]
Step 2: Apply Logarithmic Properties
Using the property of logarithms that states \( \ln(a^b) = b \cdot \ln(a) \), we can rewrite the left side:
\[
(x+2) \cdot \ln(2) = \ln(6)
\]
Step 3: Isolate \( x \)
Next, we isolate \( x \):
\[
x + 2 = \frac{\ln(6)}{\ln(2)}
\]
\[
x = \frac{\ln(6)}{\ln(2)} - 2
\]
Step 4: Calculate the Value of \( x \)
After performing the calculations, we find:
\[
x \approx 0.5849625007211561
\]
Rounding this to the nearest hundredth gives:
\[
x \approx 0.58
\]