The given equation is:
\[ \frac{1}{2}(k-5) = \frac{3}{4} \]
First, distribute the \(\frac{1}{2}\) across the terms inside the parentheses:
\[ \frac{1}{2} \cdot k - \frac{1}{2} \cdot 5 = \frac{3}{4} \]
This simplifies to:
\[ \frac{1}{2}k - \frac{5}{2} = \frac{3}{4} \]
To eliminate the fractions, multiply every term by the least common denominator (LCD) of the fractions, which is 4:
\[ 4 \left(\frac{1}{2}k\right) - 4 \left(\frac{5}{2}\right) = 4 \left(\frac{3}{4}\right) \]
\[ 2k - 10 = 3 \]
Add 10 to both sides of the equation to isolate the term with \(k\):
\[ 2k - 10 + 10 = 3 + 10 \]
\[ 2k = 13 \]
Now, divide both sides by 2 to solve for \(k\):
\[ k = \frac{13}{2} \]
\[ \boxed{k = \frac{13}{2}} \]
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