Questions: Find the maximum value of
[ P=9 x+8 y ]
subject to the following constraints:
Now, find the coordinates of the corner points.
x y
0 0
6 0
0 7
[?]
8 x+6 y leq 48
7 x+7 y leq 49
x geq 0
y geq 0
Transcript text: Find the maximum value of
\[
P=9 x+8 y
\]
subject to the following constraints:
Now, find the coordinates of the corner points.
\begin{tabular}{ll}
$x$ & $y$ \\
0 & 0 \\
6 & 0 \\
0 & 7 \\
{$[?]$}
\end{tabular}$\quad\left\{\begin{array}{l}8 x+6 y \leq 48 \\
7 x+7 y \leq 49 \\
x \geq 0 \\
y \geq 0\end{array}\right.$
Solution
Solution Steps
Step 1: Find the intersection point of the two lines
The two lines are defined by the equations:
$8x + 6y = 48$
$7x + 7y = 49$ which simplifies to $x + y = 7$ or $y = 7 - x$
Substitute $y$ in the first equation:
$8x + 6(7 - x) = 48$
$8x + 42 - 6x = 48$
$2x = 6$
$x = 3$
Now substitute $x$ back into $y = 7 - x$:
$y = 7 - 3$
$y = 4$
So the intersection point is $(3, 4)$.
Step 2: List the corner points
The corner points are $(0, 0)$, $(6, 0)$, $(0, 7)$ and $(3, 4)$.
Step 3: Evaluate P at each corner point
$P = 9x + 8y$
$(0, 0)$: $P = 9(0) + 8(0) = 0$
$(6, 0)$: $P = 9(6) + 8(0) = 54$
$(0, 7)$: $P = 9(0) + 8(7) = 56$
$(3, 4)$: $P = 9(3) + 8(4) = 27 + 32 = 59$
Final Answer:
The maximum value of P is 59. The coordinates of the missing corner point are $(3, 4)$.