Questions: Question 26 The following compound is: (R)-3-chloropent-1-ene Cl-C-CH2-CH3 H H-C=C H H O True O False

Solution Steps

The compound is named (R)-3-chloropent-1-ene. This name provides the following information:

• The compound is a pentene, indicating a five-carbon chain with a double bond.
• The double bond is located at the first carbon (1-ene).
• There is a chlorine substituent at the third carbon (3-chloro).
• The configuration at the chiral center is specified as (R).

In the compound (R)-3-chloropent-1-ene, the chiral center is at the third carbon, where the chlorine is attached. The structure around this carbon is:

• \(\ce{Cl}\) (chlorine)
• \(\ce{CH2CH3}\) (ethyl group)
• \(\ce{CH=CH2}\) (vinyl group)
• \(\ce{H}\) (hydrogen)

To determine the (R) or (S) configuration, we assign priorities to the groups attached to the chiral center based on atomic number:

1. \(\ce{Cl}\) (highest priority due to highest atomic number)
2. \(\ce{CH=CH2}\) (next highest priority)
3. \(\ce{CH2CH3}\)
4. \(\ce{H}\) (lowest priority)

With the lowest priority group (\(\ce{H}\)) pointing away from us, we trace a path from the highest priority group to the lowest:

• From \(\ce{Cl}\) to \(\ce{CH=CH2}\) to \(\ce{CH2CH3}\).

This path is clockwise, which corresponds to the (R) configuration.

The given structure should match the (R)-3-chloropent-1-ene configuration. The structure provided in the question is:

\[ \begin{array}{c} \ce{Cl-C-CH2-CH3} \\ \ce{H} \\ \ce{H-C=C} \\ \ce{H H} \end{array} \]

This structure does not clearly represent the (R)-3-chloropent-1-ene configuration, as it lacks clarity in the spatial arrangement of the groups around the chiral center.

Final Answer