Questions: Find the equation of the horizontal line that contains the point (8,-7). Express the equation using either the general form or the slope-intercept form of the equation of a line. The equation of the line is . (Type an equation.)

Find the equation of the horizontal line that contains the point (8,-7). Express the equation using either the general form or the slope-intercept form of the equation of a line.

The equation of the line is . (Type an equation.)

Transcript text: Find the equation of the horizontal line that contains the point $(8,-7)$. Express the equation using either the general form or the slope-intercept form of the equation of a line. The equation of the line is $\square$ . (Type an equation.)

Solution

Solution Steps

Step 1: Identify the Given Point

The given point is \((x_1, y_1) = (8, -7)\).

Step 2: Recognize the Constant y-value

The equation of a horizontal line passing through this point will have a constant y-value equal to \(y_1\), which is -7.

Step 3: Write the Equation in Slope-Intercept Form

The equation of the line in slope-intercept form is \(y = -7\).

Step 4: Write the Equation in General Form

Alternatively, the equation in general form is \(0x + y = -7\).

Final Answer:

The equation of the horizontal line that contains the given point \((8, -7)\) is \(y = -7\) or \(0x + y = -7\) in general form.

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