Questions: Does the equation (5 v^3-7 u^2=1) define (v) as a function of (u)?

Does the equation (5 v^3-7 u^2=1) define (v) as a function of (u)?
Transcript text: Does the equatio $5 v^{3}-7 u^{2}=1$ define $v$ as a function of $u$ ?
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Solution

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Solution Steps

Step 1: Understand the problem

The equation given is \(5v^{3} - 7u^{2} = 1\). We need to determine if this equation defines \(v\) as a function of \(u\). In other words, for each value of \(u\), does there exist exactly one corresponding value of \(v\)?

Step 2: Solve for \(v\) in terms of \(u\)

To determine if \(v\) is a function of \(u\), we can attempt to solve the equation for \(v\):

\[ 5v^{3} - 7u^{2} = 1 \]

First, isolate the term containing \(v\):

\[ 5v^{3} = 1 + 7u^{2} \]

Next, divide both sides by 5:

\[ v^{3} = \frac{1 + 7u^{2}}{5} \]

Finally, take the cube root of both sides:

\[ v = \sqrt[3]{\frac{1 + 7u^{2}}{5}} \]

Step 3: Analyze the solution

The expression \(v = \sqrt[3]{\frac{1 + 7u^{2}}{5}}\) shows that for each value of \(u\), there is exactly one corresponding value of \(v\). This is because the cube root function is a one-to-one function, meaning it maps each input to exactly one output. Therefore, \(v\) is indeed a function of \(u\).

Final Answer

Yes, the equation defines \(v\) as a function of \(u\).

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