Questions: Solve the system of equations.
y=8x
y=3x+30
Transcript text: Solve the system of equations.
\[
\begin{array}{l}
y=8 x \\
y=3 x+30
\end{array}
\]
Solution
Solution Steps
To solve the system of equations, we can set the two equations equal to each other since they both equal \( y \). This will allow us to solve for \( x \). Once we have \( x \), we can substitute it back into either equation to find \( y \).
Step 1: Set the Equations Equal
We have the system of equations:
\[
y = 8x
\]
\[
y = 3x + 30
\]
To find the values of \( x \) and \( y \), we set the two equations equal to each other:
\[
8x = 3x + 30
\]
Step 2: Solve for \( x \)
Rearranging the equation gives:
\[
8x - 3x = 30
\]
\[
5x = 30
\]
Dividing both sides by 5, we find:
\[
x = 6
\]
Step 3: Substitute \( x \) to Find \( y \)
Now, we substitute \( x = 6 \) back into one of the original equations to find \( y \). Using the first equation:
\[
y = 8(6) = 48
\]
Final Answer
The solution to the system of equations is:
\[
\boxed{x = 6}
\]
\[
\boxed{y = 48}
\]