Questions: A race car has a speed of 98 m / s. The driver hits the brakes, causing the car to slow down at a constant rate of 12 m / s^2 for a period of 8 seconds.
Compute the speed of the car at 2 s, 4 s, 6 s, and 8 s after the driver hits the brakes,
The speed of the car at 2 s is m / s,
The speed of the car at 4 s is m/s.
The speed of the car at 6 s is m / s.
The speed of the car at 8 s is m / s.
Transcript text: A race car has a speed of $98 \mathrm{~m} / \mathrm{s}$. The driver hits the brakes, causing the car to slow down at a constant rate of $12 \mathrm{~m} / \mathrm{s}^{2}$ for a period of 8 seconds.
Compute the speed of the car at $2 \mathrm{~s}, 4 \mathrm{~s}, 6 \mathrm{~s}$, and 8 s after the driver hits the brakes,
The speed of the car at 2 s is $\square$ $\square$ $\mathrm{m} / \mathrm{s}$,
The speed of the car at 4 s is $\square$ m's.
The speed of the car at 6 s is $\square$ $\mathrm{m} / \mathrm{s}$.
The speed of the car at 8 s is $\square$ $\mathrm{m} / \mathrm{s}$.
Solution
Solution Steps
Step 1: Identify the initial conditions and given data
The initial speed of the race car is \( v_0 = 98 \, \mathrm{m/s} \). The car decelerates at a constant rate of \( a = -12 \, \mathrm{m/s^2} \). We need to find the speed of the car at \( t = 2 \, \mathrm{s}, 4 \, \mathrm{s}, 6 \, \mathrm{s}, \) and \( 8 \, \mathrm{s} \).
Step 2: Use the kinematic equation for velocity
The kinematic equation for velocity under constant acceleration is:
\[ v = v_0 + at \]
Step 3: Calculate the speed at \( t = 2 \, \mathrm{s} \)
Substitute \( v_0 = 98 \, \mathrm{m/s} \), \( a = -12 \, \mathrm{m/s^2} \), and \( t = 2 \, \mathrm{s} \) into the equation:
\[ v = 98 + (-12)(2) \]
\[ v = 98 - 24 \]
\[ v = 74 \, \mathrm{m/s} \]
Step 4: Calculate the speed at \( t = 4 \, \mathrm{s} \)
Substitute \( v_0 = 98 \, \mathrm{m/s} \), \( a = -12 \, \mathrm{m/s^2} \), and \( t = 4 \, \mathrm{s} \) into the equation:
\[ v = 98 + (-12)(4) \]
\[ v = 98 - 48 \]
\[ v = 50 \, \mathrm{m/s} \]
Step 5: Calculate the speed at \( t = 6 \, \mathrm{s} \)
Substitute \( v_0 = 98 \, \mathrm{m/s} \), \( a = -12 \, \mathrm{m/s^2} \), and \( t = 6 \, \mathrm{s} \) into the equation:
\[ v = 98 + (-12)(6) \]
\[ v = 98 - 72 \]
\[ v = 26 \, \mathrm{m/s} \]
Step 6: Calculate the speed at \( t = 8 \, \mathrm{s} \)
Substitute \( v_0 = 98 \, \mathrm{m/s} \), \( a = -12 \, \mathrm{m/s^2} \), and \( t = 8 \, \mathrm{s} \) into the equation:
\[ v = 98 + (-12)(8) \]
\[ v = 98 - 96 \]
\[ v = 2 \, \mathrm{m/s} \]
Final Answer
The speed of the car at 2 s is \(\boxed{74 \, \mathrm{m/s}}\).
The speed of the car at 4 s is \(\boxed{50 \, \mathrm{m/s}}\).
The speed of the car at 6 s is \(\boxed{26 \, \mathrm{m/s}}\).
The speed of the car at 8 s is \(\boxed{2 \, \mathrm{m/s}}\).