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Homework 3.5: Exponential and Logarithmic Models
Score: 18.5 / 25 10 / 13 answered
Question 12
x 1 2 3 4 5 6
y 726 960 1160 1663 2116 2772
Use regression to find an exponential equation that best fits the data above. The equation has form y = a * b^x where:
a =□
b =□
Transcript text: KeMyTcC: Student
Homework 3.5: Exponential and Logarithmic Models
Score: $18.5 / 25 \quad 10 / 13$ answered
Question 12
\begin{tabular}{|r|r|r|r|r|r|r|}
\hline $\mathbf{x}$ & 1 & 2 & 3 & 4 & 5 & 6 \\
\hline $\mathbf{y}$ & 726 & 960 & 1160 & 1663 & 2116 & 2772 \\
\hline
\end{tabular}
Use regression to find an exponential equation that best fits the data above. The equation has form $y=a b^{x}$ where:
\[
\begin{array}{l}
\mathrm{a}=\square \\
\mathrm{b}=\square
\end{array}
\]
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Solution
Solution Steps
Step 1: Transform the exponential equation to a linear form
By taking the natural logarithm on both sides of the equation $y = a b^{x}$, we get $\ln(y) = \ln(a) + x\ln(b)$.
This transformation allows us to use linear regression to find the coefficients $\ln(a)$ and $\ln(b)$.
Step 2: Perform linear regression
Using the transformed data points $(x, \ln(y))$, linear regression yields the coefficients $\ln(a) = 6.309$ and $\ln(b) = 0.269$.
Step 3: Calculate $a$ and $b$
After obtaining the coefficients from the linear regression, we calculate $a = e^{\ln(a)} = 549.456$ and $b = e^{\ln(b)} = 1.309$.
Final Answer:
The exponential equation that best fits the given data is $y = 549.456 \cdot 1.309^{x}$.