Questions: The frequency distribution below summarizes the home sale prices in the city of Summerhill for the month of June. Determine the width of each class. Round to the nearest whole number as needed. Sale Price (in thousand ) Frequency 80.0-110.9 2 111.0-141.9 5 142.0-172.9 7 173.0-203.9 10 204.0-234.9 3 235.0-265.9 1 A. 28 B. 61 C. 31 D. 30

The frequency distribution below summarizes the home sale prices in the city of Summerhill for the month of June. Determine the width of each class. Round to the nearest whole number as needed. Sale Price (in thousand ) Frequency 80.0-110.9 2 111.0-141.9 5 142.0-172.9 7 173.0-203.9 10 204.0-234.9 3 235.0-265.9 1 A. 28 B. 61 C. 31 D. 30
Transcript text: The frequency distribution below summarizes the home sale prices in the city of Summerhill for the month of June. Determine the width of each class Round to the nearest whiche number as needed. \begin{tabular}{r|c} Sale Price (in thousand \$) & Frequency \\ \hline $80.0-110.9$ & 2 \\ $111.0-141.9$ & 5 \\ $142.0-172.9$ & 7 \\ $173.0-203.9$ & 10 \\ $204.0-234.9$ & 3 \\ $235.0-265.9$ & 1 \end{tabular} A. 28 B. 61 C. 31 D. 30
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Solution

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Solution Steps

To determine the width of each class in the frequency distribution, we need to subtract the lower limit of a class from the lower limit of the next class. This will give us the class width.

Step 1: Identify the Lower Limits of Each Class

The lower limits of each class are given as: \[ 80.0, 111.0, 142.0, 173.0, 204.0, 235.0 \]

Step 2: Calculate the Class Width

To find the class width, subtract the lower limit of the first class from the lower limit of the second class: \[ \text{Class Width} = 111.0 - 80.0 = 31.0 \]

Final Answer

\(\boxed{31}\)

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