Questions: CHM-1C Measurement and Matter Predicting ionic compounds formed by two elements Decide whether each pair of elements in the table below will form an ionic compound. I space provided. element #1 element #2 Forms ionic compound? empirical formula of ionic compound --- --- --- --- fluorine oxygen yes no — iodine rubidium yes no oxygen magnesium yes no bromine lithium yes no

CHM-1C Measurement and Matter Predicting ionic compounds formed by two elements Decide whether each pair of elements in the table below will form an ionic compound. I space provided. element #1 element #2 Forms ionic compound? empirical formula of ionic compound --- --- --- --- fluorine oxygen yes no — iodine rubidium yes no oxygen magnesium yes no bromine lithium yes no
Transcript text: CHM-1C Measurement and Matter Predicting ionic compounds formed by two elements Decide whether each pair of elements in the table below will form an ionic compound. I space provided. \begin{tabular}{|c|c|c|c|c|} \hline element \#1 & element \#2 & \multicolumn{2}{|l|}{Forms ionic compound?} & empirical formula of ionic compound \\ \hline fluorine & oxygen & yes & no & — \\ \hline iodine & rubidium & yes & Ono & $\square$ \\ \hline oxygen & magnesium & yes & no & $\square$ \\ \hline bromine & lithium & yes & no & $\square$ \\ \hline \end{tabular}
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Solution

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Solution Steps

Step 1: Determine Ionic Compound Formation

To determine if a pair of elements will form an ionic compound, we need to consider their positions in the periodic table. Ionic compounds typically form between metals and non-metals. Metals tend to lose electrons and form cations, while non-metals tend to gain electrons and form anions.

Step 2: Analyze Each Pair of Elements
  • Fluorine and Oxygen: Both are non-metals. Non-metals do not typically form ionic compounds with each other. Therefore, they do not form an ionic compound.
  • Iodine and Rubidium: Iodine is a non-metal, and rubidium is a metal. This pair can form an ionic compound.
  • Oxygen and Magnesium: Oxygen is a non-metal, and magnesium is a metal. This pair can form an ionic compound.
  • Bromine and Lithium: Bromine is a non-metal, and lithium is a metal. This pair can form an ionic compound.
Step 3: Determine Empirical Formulas

For pairs that form ionic compounds, determine the empirical formula by balancing the charges of the ions:

  • Iodine and Rubidium: Rubidium forms a \( \text{Rb}^+ \) ion, and iodine forms an \( \text{I}^- \) ion. The empirical formula is \( \text{RbI} \).
  • Oxygen and Magnesium: Magnesium forms a \( \text{Mg}^{2+} \) ion, and oxygen forms an \( \text{O}^{2-} \) ion. The empirical formula is \( \text{MgO} \).
  • Bromine and Lithium: Lithium forms a \( \text{Li}^+ \) ion, and bromine forms a \( \text{Br}^- \) ion. The empirical formula is \( \text{LiBr} \).

Final Answer

  • Fluorine and Oxygen: No ionic compound.
  • Iodine and Rubidium: Forms ionic compound, empirical formula is \(\boxed{\text{RbI}}\).
  • Oxygen and Magnesium: Forms ionic compound, empirical formula is \(\boxed{\text{MgO}}\).
  • Bromine and Lithium: Forms ionic compound, empirical formula is \(\boxed{\text{LiBr}}\).
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