Questions: Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.
Ca3(PO4)2(s) + SiO2(s) + C(s) -> CaSiO3(s) + P4(s) + CO(g)
Transcript text: Balance the chemical equation below using the smallest possible whole number stoichiometric coefficients.
\[
\left.\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s)+\mathrm{SiO}_{2}(s)+\mathrm{C}(s) \rightarrow \mathrm{CaSiO}_{3}(s)+\mathrm{P}_{4}(s)+\mathrm{CO}(g)\right]
\]
Solution
Solution Steps
Step 1: Write the Unbalanced Equation
The given chemical equation is:
\[
\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s) + \mathrm{SiO}_{2}(s) + \mathrm{C}(s) \rightarrow \mathrm{CaSiO}_{3}(s) + \mathrm{P}_{4}(s) + \mathrm{CO}(g)
\]
To balance phosphorus, we need 4 phosphorus atoms on both sides. Since \(\mathrm{P}_{4}\) has 4 phosphorus atoms, we need 2 \(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) on the reactant side:
\[
2\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s) + \mathrm{SiO}_{2}(s) + \mathrm{C}(s) \rightarrow \mathrm{CaSiO}_{3}(s) + \mathrm{P}_{4}(s) + \mathrm{CO}(g)
\]
Step 4: Balance the Calcium Atoms
Now, we have 6 calcium atoms on the reactant side. We need 6 \(\mathrm{CaSiO}_{3}\) on the product side:
\[
2\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s) + \mathrm{SiO}_{2}(s) + \mathrm{C}(s) \rightarrow 6\mathrm{CaSiO}_{3}(s) + \mathrm{P}_{4}(s) + \mathrm{CO}(g)
\]
Step 5: Balance the Silicon Atoms
We have 6 silicon atoms needed on the reactant side, so we need 6 \(\mathrm{SiO}_{2}\):
\[
2\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s) + 6\mathrm{SiO}_{2}(s) + \mathrm{C}(s) \rightarrow 6\mathrm{CaSiO}_{3}(s) + \mathrm{P}_{4}(s) + \mathrm{CO}(g)
\]
Step 6: Balance the Carbon and Oxygen Atoms
Now, balance the carbon and oxygen atoms. We have 16 oxygen atoms on the reactant side (16 from \(\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) and 12 from \(\mathrm{SiO}_{2}\)), and 18 on the product side (18 from \(\mathrm{CaSiO}_{3}\)). We need 10 \(\mathrm{CO}\) to balance the oxygen:
\[
2\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s) + 6\mathrm{SiO}_{2}(s) + 10\mathrm{C}(s) \rightarrow 6\mathrm{CaSiO}_{3}(s) + \mathrm{P}_{4}(s) + 10\mathrm{CO}(g)
\]
Final Answer
The balanced chemical equation is:
\[
\boxed{2\mathrm{Ca}_{3}\left(\mathrm{PO}_{4}\right)_{2}(s) + 6\mathrm{SiO}_{2}(s) + 10\mathrm{C}(s) \rightarrow 6\mathrm{CaSiO}_{3}(s) + \mathrm{P}_{4}(s) + 10\mathrm{CO}(g)}
\]