Questions: An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 140 engines and the mean pressure was 6.8 lbs / square inch. Assume the standard deviation is known to be 0.8. If the valve was designed to produce a mean pressure of 6.9 lbs / square inch, is there sufficient evidence at the 0.1 level that the valve does not perform to the specifications?
State the null and alternative hypotheses for the above scenario.
H0:
Ha:
Transcript text: An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 140 engines and the mean pressure was 6.8 $\mathrm{lbs} /$ square inch. Assume the standard deviation is known to be 0.8 . If the valve was designed to produce a mean pressure of $6.9 \mathrm{lbs} / \mathrm{square}$ inch, is there sufficient evidence at the 0.1 level that the valve does not perform to the specifications?
State the null and alternative hypotheses for the above scenario.
Answer
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\[
\begin{array}{l}
H_{0}: \square \\
H_{a}: \square
\end{array}
\]
Solution
Solution Steps
Step 1: State the Hypotheses
We define the null and alternative hypotheses as follows:
Null Hypothesis \( H_0 \): The valve produces a mean pressure of \( 6.9 \, \text{lbs/square inch} \).
Alternative Hypothesis \( H_a \): The valve does not produce a mean pressure of \( 6.9 \, \text{lbs/square inch} \).
Step 2: Calculate the Standard Error
The standard error \( SE \) is calculated using the formula:
\[
SE = \frac{\sigma}{\sqrt{n}} = \frac{0.8}{\sqrt{140}} \approx 0.0676
\]
Step 3: Calculate the Test Statistic
The Z-test statistic is calculated using the formula:
\[
Z = \frac{\bar{x} - \mu_0}{SE} = \frac{6.8 - 6.9}{0.0676} \approx -1.479
\]
Step 4: Calculate the P-value
For a two-tailed test, the P-value is calculated as:
\[
P = 2 \times (1 - T(|z|)) \approx 0.1391
\]
Step 5: Decision Rule
We compare the P-value to the significance level \( \alpha = 0.1 \):
If \( P < \alpha \), we reject the null hypothesis.
If \( P \geq \alpha \), we fail to reject the null hypothesis.
Step 6: Conclusion
Since \( P \approx 0.1391 \) is greater than \( \alpha = 0.1 \), we fail to reject the null hypothesis. Therefore, there is not sufficient evidence that the valve does not perform to the specifications.