Questions: An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 140 engines and the mean pressure was 6.8 lbs / square inch. Assume the standard deviation is known to be 0.8. If the valve was designed to produce a mean pressure of 6.9 lbs / square inch, is there sufficient evidence at the 0.1 level that the valve does not perform to the specifications? State the null and alternative hypotheses for the above scenario. H0: Ha:

An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 140 engines and the mean pressure was 6.8 lbs / square inch. Assume the standard deviation is known to be 0.8. If the valve was designed to produce a mean pressure of 6.9 lbs / square inch, is there sufficient evidence at the 0.1 level that the valve does not perform to the specifications?

State the null and alternative hypotheses for the above scenario.

H0:  
Ha:
Transcript text: An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 140 engines and the mean pressure was 6.8 $\mathrm{lbs} /$ square inch. Assume the standard deviation is known to be 0.8 . If the valve was designed to produce a mean pressure of $6.9 \mathrm{lbs} / \mathrm{square}$ inch, is there sufficient evidence at the 0.1 level that the valve does not perform to the specifications? State the null and alternative hypotheses for the above scenario. Answer Tables Keypad Keyboard Shortcuts \[ \begin{array}{l} H_{0}: \square \\ H_{a}: \square \end{array} \]
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Solution

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Solution Steps

Step 1: State the Hypotheses

We define the null and alternative hypotheses as follows:

  • Null Hypothesis \( H_0 \): The valve produces a mean pressure of \( 6.9 \, \text{lbs/square inch} \).
  • Alternative Hypothesis \( H_a \): The valve does not produce a mean pressure of \( 6.9 \, \text{lbs/square inch} \).
Step 2: Calculate the Standard Error

The standard error \( SE \) is calculated using the formula: \[ SE = \frac{\sigma}{\sqrt{n}} = \frac{0.8}{\sqrt{140}} \approx 0.0676 \]

Step 3: Calculate the Test Statistic

The Z-test statistic is calculated using the formula: \[ Z = \frac{\bar{x} - \mu_0}{SE} = \frac{6.8 - 6.9}{0.0676} \approx -1.479 \]

Step 4: Calculate the P-value

For a two-tailed test, the P-value is calculated as: \[ P = 2 \times (1 - T(|z|)) \approx 0.1391 \]

Step 5: Decision Rule

We compare the P-value to the significance level \( \alpha = 0.1 \):

  • If \( P < \alpha \), we reject the null hypothesis.
  • If \( P \geq \alpha \), we fail to reject the null hypothesis.
Step 6: Conclusion

Since \( P \approx 0.1391 \) is greater than \( \alpha = 0.1 \), we fail to reject the null hypothesis. Therefore, there is not sufficient evidence that the valve does not perform to the specifications.

Final Answer

\(\boxed{\text{Fail to reject } H_0}\)

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