Let \( a = 5 \), \( b = 8 \), and \( c = 9 \).
Using the Law of Cosines, we calculate \( \cos(A) \) as follows: \[ \cos(A) = \frac{b^2 + c^2 - a^2}{2bc} \] Substituting the values: \[ \cos(A) = \frac{8^2 + 9^2 - 5^2}{2 \cdot 8 \cdot 9} \]
Calculating the squares: \[ \cos(A) = \frac{64 + 81 - 25}{144} = \frac{120}{144} = \frac{5}{6} \]
To find \( A \), we take the inverse cosine: \[ A = \cos^{-1}\left(\frac{5}{6}\right) \]
Finally, convert \( A \) from radians to degrees: \[ A \approx 33.56^\circ \]
\(\boxed{33.56^\circ}\)
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