Questions: Graphing and Functions Question 13, Part 1 of 2 Evaluate the function f(x)=x^2-5 at the given value of the variable. a. f(-4) b. f(3) a. f(-4)= (Simplify your answer.)

The value of the function at $x = -4$ is $f(-4) = 11$, rounded to 0 decimal places.

Given that $a = 1$, $b = 0$, $c = -5$, and $x = 3$, we substitute these into the function to get: $$f(3) = 1(3)^2 + 0(3) - 5$$

Since $x$ is a specific value, we directly compute $f(3) = 1_3^2 + 0_3 - 5$.

The value of the function at $x = 3$ is $f(3) = 4$, rounded to 0 decimal places.