Questions: Divide the following two complex numbers.
(4-3 i)/(3+2 i)
a.) (6/5)-(17/5) i
b.) (18/5)-(17/5) i
c.) (6/13)-(17/13) i
d.) (18/13)-(17/13) i
Transcript text: Divide the following two complex numbers.
\[
\frac{4-3 i}{3+2 i}
\]
a.) $\frac{6}{5}-\frac{17}{5} i$
b.) $\frac{18}{5}-\frac{17}{5} i$
c.) $\frac{6}{13}-\frac{17}{13} i$
d.) $\frac{18}{13}-\frac{17}{13} i$
Solution
Solution Steps
Step 1: Define the Complex Numbers
Let z1=4−3i (the numerator) and z2=3+2i (the denominator).
Step 2: Find the Conjugate of the Denominator
The conjugate of the denominator z2 is z2=3−2i.
Step 3: Multiply by the Conjugate
Multiply both the numerator and the denominator by the conjugate of the denominator:
z2z1=(3+2i)(3−2i)(4−3i)(3−2i)
Step 4: Simplify the Denominator
Calculate the denominator:
(3+2i)(3−2i)=32−(2i)2=9−(−4)=9+4=13
Step 5: Expand the Numerator
Expand the numerator:
(4−3i)(3−2i)=4⋅3+4⋅(−2i)−3i⋅3−3i⋅(−2i)=12−8i−9i+6=18−17i
Step 6: Combine the Results
Now, combine the results:
1318−17i=1318−1317i
Step 7: Final Result
Thus, the result of dividing the two complex numbers is:
1318−1317i