Questions: If pointer 1 is spun and then pointer 2 is spun, determine the probability of landing on yellow on both spins. Pointer 2 The probability is (Type an integer or a simplified fraction.)

If pointer 1 is spun and then pointer 2 is spun, determine the probability of landing on yellow on both spins. Pointer 2 The probability is (Type an integer or a simplified fraction.)
Transcript text: If pointer 1 is spun and then pointer 2 is spun, determine the probability of landing on yellow on both spins. Pointer 2 The probability is $\square$ (Type an integer or a simplified fraction.)
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Solution

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Solution Steps

Step 1: Probability of landing on yellow for Pointer 1

Pointer 1 is divided into three equal sections. One section is yellow. The probability of landing on yellow for Pointer 1 is 1/3.

Step 2: Probability of landing on yellow for Pointer 2

Pointer 2 is divided into six equal sections. Two sections are yellow. The probability of landing on yellow for Pointer 2 is 2/6 which simplifies to 1/3.

Step 3: Probability of landing on yellow for both pointers

Since the two events are independent, the probability of both occurring is the product of their individual probabilities. The probability of both pointers landing on yellow is (1/3) * (1/3) = 1/9.

Final Answer: The probability is 1/9

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