Questions: Draw the Lewis electron dot structure for GeCl2. What is the VSEPR shape of the particle? - bent - tetrahedral - linear - trigonal planar

Draw the Lewis electron dot structure for GeCl2. What is the VSEPR shape of the particle? - bent - tetrahedral - linear - trigonal planar
Transcript text: Draw the Lewis electron dot structure for $\mathrm{GeCl}_{2}$. What is the VSEPR shape of the particle? bent tetrahedral linear trigonal planar
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Solution

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Solution Steps

Step 1: Determine the Total Number of Valence Electrons

Germanium (Ge) is in group 14 of the periodic table and has 4 valence electrons. Chlorine (Cl) is in group 17 and has 7 valence electrons. Since there are two chlorine atoms, the total number of valence electrons is:

\[ 4 \, (\text{from Ge}) + 2 \times 7 \, (\text{from Cl}) = 18 \, \text{valence electrons} \]

Step 2: Draw the Lewis Structure
  1. Place the germanium atom in the center as it is less electronegative than chlorine.
  2. Connect each chlorine atom to the germanium atom with a single bond. This uses 4 electrons (2 for each bond).
  3. Distribute the remaining 14 electrons to satisfy the octet rule for each chlorine atom. Each chlorine will have 6 more electrons as lone pairs, completing their octets.
  4. The germanium atom will have 2 lone pairs remaining after the bonds.

The Lewis structure is:

\[ \begin{array}{c} \text{Cl} \, : \, \text{Ge} \, : \, \text{Cl} \\ \end{array} \]

Step 3: Determine the VSEPR Shape

The central germanium atom is surrounded by two bonding pairs and two lone pairs of electrons. According to VSEPR theory, this arrangement corresponds to a "bent" shape due to the repulsion between the lone pairs, which pushes the bonding pairs closer together.

Final Answer

The VSEPR shape of the particle is \(\boxed{\text{bent tetrahedral}}\).

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