Questions: Given below is a data set: 75 66 54 78 64 58 69 53 65 70 74 65 74 65 58 68 55 65 88 68 84 53 63 51 84 67 64 50 61 68 Examine the data above by reviewing the stem-and-leaf plot. Here is the start of the plot. missing values? 5# 01334588 6# 13445555678889 7# 04458 8#

Given below is a data set:
75 66 54 78 64
58 69 53 65 70
74 65 74 65 58
68 55 65 88 68
84 53 63 51 84
67 64 50 61 68

Examine the data above by reviewing the stem-and-leaf plot. Here is the start of the plot. missing values?
5# 01334588
6# 13445555678889
7# 04458
8#
Transcript text: Given below is a data set: \begin{tabular}{|l|l|l|l|l|} \hline 75 & 66 & 54 & 78 & 64 \\ \hline 58 & 69 & 53 & 65 & 70 \\ \hline 74 & 65 & 74 & 65 & 58 \\ \hline 68 & 55 & 65 & 88 & 68 \\ \hline 84 & 53 & 63 & 51 & 84 \\ \hline 67 & 64 & 50 & 61 & 68 \\ \hline \end{tabular} Examine the data above by reviewing the stem-and-leaf plot. Here is the start of the plot. missing values? \[ \begin{array}{l|l} \text { 5\# } & 01334588 \\ \text { 6\# } & 13445555678889 \\ \text { 7\# } & 04458 \\ \text { 8\# } & \end{array} \]
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Solution

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Solution Steps

Step 1: Calculate the Mean

The mean \( \mu \) of the dataset is calculated using the formula:

\[ \mu = \frac{\sum_{i=1}^N x_i}{N} \]

For the given dataset, the sum of the values is \( 1977 \) and the number of values \( N = 30 \). Thus, the mean is:

\[ \mu = \frac{1977}{30} = 65.9 \]

Step 2: Calculate the Median

To find the median, we first sort the data:

\[ \text{Sorted data} = [50, 51, 53, 53, 54, 55, 58, 58, 61, 63, 64, 64, 65, 65, 65, 65, 66, 67, 68, 68, 68, 69, 70, 74, 74, 75, 78, 84, 84, 88] \]

Since \( N = 30 \) (even), the median \( Q \) is calculated as:

\[ \text{Rank} = Q \times (N + 1) = 0.5 \times (30 + 1) = 15.5 \]

This means we take the average of the 15th and 16th values:

\[ Q = \frac{X_{\text{lower}} + X_{\text{upper}}}{2} = \frac{65 + 65}{2} = 65.0 \]

Step 3: Calculate Variance and Standard Deviation

The variance \( \sigma^2 \) is calculated using the formula:

\[ \sigma^2 = \frac{\sum (x_i - \mu)^2}{n-1} \]

Substituting the values, we find:

\[ \sigma^2 = 95.89 \]

The standard deviation \( \sigma \) is then:

\[ \sigma = \sqrt{95.89} \approx 9.79 \]

Final Answer

  • Mean: \( \mu = 65.9 \)
  • Median: \( Q = 65.0 \)
  • Variance: \( \sigma^2 = 95.89 \)
  • Standard Deviation: \( \sigma \approx 9.79 \)

Thus, the final boxed answers are:

\[ \boxed{\mu = 65.9} \] \[ \boxed{Q = 65.0} \] \[ \boxed{\sigma^2 = 95.89} \] \[ \boxed{\sigma \approx 9.79} \]

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