The mean \( \mu \) of the dataset is calculated using the formula:
\[
\mu = \frac{\sum_{i=1}^N x_i}{N}
\]
For the given dataset, the sum of the values is \( 1977 \) and the number of values \( N = 30 \). Thus, the mean is:
\[
\mu = \frac{1977}{30} = 65.9
\]
To find the median, we first sort the data:
\[
\text{Sorted data} = [50, 51, 53, 53, 54, 55, 58, 58, 61, 63, 64, 64, 65, 65, 65, 65, 66, 67, 68, 68, 68, 69, 70, 74, 74, 75, 78, 84, 84, 88]
\]
Since \( N = 30 \) (even), the median \( Q \) is calculated as:
\[
\text{Rank} = Q \times (N + 1) = 0.5 \times (30 + 1) = 15.5
\]
This means we take the average of the 15th and 16th values:
\[
Q = \frac{X_{\text{lower}} + X_{\text{upper}}}{2} = \frac{65 + 65}{2} = 65.0
\]
The variance \( \sigma^2 \) is calculated using the formula:
\[
\sigma^2 = \frac{\sum (x_i - \mu)^2}{n-1}
\]
Substituting the values, we find:
\[
\sigma^2 = 95.89
\]
The standard deviation \( \sigma \) is then:
\[
\sigma = \sqrt{95.89} \approx 9.79
\]
- Mean: \( \mu = 65.9 \)
- Median: \( Q = 65.0 \)
- Variance: \( \sigma^2 = 95.89 \)
- Standard Deviation: \( \sigma \approx 9.79 \)
Thus, the final boxed answers are:
\[
\boxed{\mu = 65.9}
\]
\[
\boxed{Q = 65.0}
\]
\[
\boxed{\sigma^2 = 95.89}
\]
\[
\boxed{\sigma \approx 9.79}
\]