Questions: Determine the volume (in L ) of a 3.62 M solution that contains 1.18 mol ZnBr2. Be sure your answer has the correct number of significant figures.

Determine the volume (in L ) of a 3.62 M solution that contains 1.18 mol ZnBr2. Be sure your answer has the correct number of significant figures.

Transcript text: Determine the volume (in L ) of a 3.62 M solution that contains $1.18 \mathrm{~mol} \mathrm{ZnBr}_{2}$. Be sure your answer has the correct number of significant figures.

Solution

Solution Steps

Step 1: Understand the Problem

We need to find the volume of a solution in liters given its molarity and the amount of solute in moles. The molarity (M) is given as 3.62 M, and the amount of solute is 1.18 moles of $\mathrm{ZnBr}_2$.

Step 2: Use the Molarity Formula

The formula for molarity is: \[ M = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \] We can rearrange this formula to solve for the volume of the solution: \[ \text{Volume of solution in liters} = \frac{\text{moles of solute}}{M} \]

Step 3: Calculate the Volume

Substitute the given values into the rearranged formula: \[ \text{Volume of solution in liters} = \frac{1.18 \, \text{mol}}{3.62 \, \text{M}} \]

Step 4: Perform the Calculation

Calculate the volume: \[ \text{Volume of solution in liters} = \frac{1.18}{3.62} \approx 0.3251 \, \text{L} \]