Questions: 1. If PQ=PQ, then PQ ≅ PQ
2. If K is between J and L, then JK+KL=JL
3. EF ≅ EF
4. If RS=TU, then RS+XY=TU+XY
5. If AB=DE, then DE=AB
6. If Y is the midpoint of XZ, then XY=YZ
7. If FG ≅ HI and HI ≅ JK, then FG ≅ JK
8. If AB+CD=EF+CD, then AB=EF
9. If PQ+RS=TV and RS=WX, then PQ+WX=TV
10. If LP=PN, and LrP, and N are collinear, then P is the midpoint of LN
11. If UV ≅ UV, then UV=UV
12. If CD+DE=CE, then CD=CE-DE
Transcript text: 1. If $P Q=P Q$, then $\overline{P Q} \cong \overline{P Q}$
2. If $K$ is between $J$ and $L$, then $J K+K L=J L$
3. $\overline{E F} \cong \overline{E F}$
4. If $R S=T U$, then $R S+X Y=T U+X Y$
5. If $A B=D E$, then $D E=A B$
6. If $Y$ is the midpoint of $\overline{X Z}$, then $X Y=Y Z$
7. If $\overline{F G} \cong \overline{H I}$ and $\overline{H I} \cong \overline{J K}$, then $\overline{F G} \cong \overline{J K}$
8. If $A B+C D=E F+C D$, then $A B=E F$
9. If $P Q+R S=T V$ and $R S=W X$, then $P Q+W X=T V$
10. If $L P=P N$, and $L_{r} P$, and $N$ are collinear, then $P$ is the midpoint of $\overline{L N}$
11. If $\overline{U V} \cong \overline{U V}$, then $U V=U V$
12. If $C D+D E=C E$, then $C D=C E-D E$
Solution
Solution Steps
Solution Approach
The statement is a direct application of the Reflexive Property of Congruence, which states that any geometric figure is congruent to itself.
This statement uses the Segment Addition Postulate, which states that if a point \( K \) lies on a line segment \( \overline{JL} \), then the sum of the lengths of \( \overline{JK} \) and \( \overline{KL} \) is equal to the length of \( \overline{JL} \).
This is another application of the Reflexive Property of Congruence, which states that any geometric figure is congruent to itself.
Step 1: Reflexive Property of Congruence
According to the Reflexive Property of Congruence, we have:
\[
\overline{PQ} \cong \overline{PQ}
\]
This states that any segment is congruent to itself.
Step 2: Segment Addition Postulate
Using the Segment Addition Postulate, if \( K \) is between \( J \) and \( L \), then:
\[
JK + KL = JL
\]
Given \( JK = 5 \) and \( KL = 7 \), we can calculate:
\[
JL = 5 + 7 = 12
\]
Step 3: Reflexive Property of Congruence
Again applying the Reflexive Property of Congruence, we have:
\[
\overline{EF} \cong \overline{EF}
\]
This confirms that any segment is congruent to itself.