Solve the system of differential equations using the method of variation of parameters.
Identify the system and initial conditions.
The system is given by:
\[
\left[\begin{array}{l} x^{\prime} \\ y^{\prime} \end{array}\right]=\frac{1}{t}\left[\begin{array}{ll} 5 & 1 \\ 3 & 3 \end{array}\right]\left[\begin{array}{l} x \\ y \end{array}\right]+\left[\begin{array}{l} 5 \\ 5 \end{array}\right]
\]
with initial condition \(\mathbf{x}(1)=\left[\begin{array}{l} 0 \\ 2 \end{array}\right]\). The fundamental matrix is \(\mathbf{X}(t)=\left[\begin{array}{cc} t^{2} & t^{6} \\ -3 t^{2} & t^{6} \end{array}\right]\).
Apply the method of variation of parameters.
Let \(\mathbf{x}(t) = \mathbf{X}(t) \mathbf{u}(t)\), where \(\mathbf{u}(t)\) is a vector function to be determined. Then \(\mathbf{x}^{\prime}(t) = \mathbf{X}^{\prime}(t) \mathbf{u}(t) + \mathbf{X}(t) \mathbf{u}^{\prime}(t)\). Substituting into the system, we have:
\[
\mathbf{X}^{\prime}(t) \mathbf{u}(t) + \mathbf{X}(t) \mathbf{u}^{\prime}(t) = \frac{1}{t} \mathbf{A} \mathbf{X}(t) \mathbf{u}(t) + \mathbf{g}(t)
\]
where \(\mathbf{A} = \left[\begin{array}{ll} 5 & 1 \\ 3 & 3 \end{array}\right]\) and \(\mathbf{g}(t) = \left[\begin{array}{l} 5 \\ 5 \end{array}\right]\).
Simplify the equation using the properties of the fundamental matrix.
Since \(\mathbf{X}(t)\) is a fundamental matrix, \(\mathbf{X}^{\prime}(t) = \frac{1}{t} \mathbf{A} \mathbf{X}(t)\). Therefore, the equation simplifies to:
\[
\mathbf{X}(t) \mathbf{u}^{\prime}(t) = \mathbf{g}(t)
\]
Thus, \(\mathbf{u}^{\prime}(t) = \mathbf{X}^{-1}(t) \mathbf{g}(t)\).
Calculate the inverse of the fundamental matrix \(\mathbf{X}(t)\).
The determinant of \(\mathbf{X}(t)\) is \(t^{2} \cdot t^{6} - (-3 t^{2}) \cdot t^{6} = t^{8} + 3 t^{8} = 4 t^{8}\). Therefore,
\[
\mathbf{X}^{-1}(t) = \frac{1}{4 t^{8}} \left[\begin{array}{cc} t^{6} & -t^{6} \\ 3 t^{2} & t^{2} \end{array}\right] = \frac{1}{4} \left[\begin{array}{cc} t^{-2} & -t^{-2} \\ 3 t^{-6} & t^{-6} \end{array}\right]
\]
Find \(\mathbf{u}^{\prime}(t)\) and integrate to find \(\mathbf{u}(t)\).
\[
\mathbf{u}^{\prime}(t) = \mathbf{X}^{-1}(t) \mathbf{g}(t) = \frac{1}{4} \left[\begin{array}{cc} t^{-2} & -t^{-2} \\ 3 t^{-6} & t^{-6} \end{array}\right] \left[\begin{array}{l} 5 \\ 5 \end{array}\right] = \frac{1}{4} \left[\begin{array}{l} 0 \\ 20 t^{-6} \end{array}\right] = \left[\begin{array}{c} 0 \\ 5 t^{-6} \end{array}\right]
\]
Integrating, we get:
\[
\mathbf{u}(t) = \int \mathbf{u}^{\prime}(t) dt = \int \left[\begin{array}{c} 0 \\ 5 t^{-6} \end{array}\right] dt = \left[\begin{array}{c} c_{1} \\ -t^{-5} \end{array}\right]
\]
where \(c_{1}\) is a constant of integration.
Find the homogeneous and particular solutions.
The homogeneous solution is:
\[
\mathbf{x}(t) = \mathbf{X}(t) \mathbf{u}(t) = \left[\begin{array}{cc} t^{2} & t^{6} \\ -3 t^{2} & t^{6} \end{array}\right] \left[\begin{array}{c} c_{1} \\ -t^{-5} \end{array}\right] = \left[\begin{array}{c} c_{1} t^{2} - t \\ -3 c_{1} t^{2} - t \end{array}\right]
\]
The particular solution is:
\[
\mathbf{x}_p(t) = \left[\begin{array}{cc} t^{2} & t^{6} \\ -3 t^{2} & t^{6} \end{array}\right] \left[\begin{array}{c} 0 \\ -t^{-5} \end{array}\right] = \left[\begin{array}{c} -t \\ -t \end{array}\right]
\]
Combine solutions and apply initial conditions.
The general solution is:
\[
\mathbf{x}(t) = \left[\begin{array}{c} c_{1} t^{2} + c_{2} t^{6} - t \\ -3 c_{1} t^{2} + c_{2} t^{6} - t \end{array}\right]
\]
Apply the initial condition \(\mathbf{x}(1) = \left[\begin{array}{l} 0 \\ 2 \end{array}\right]\):
\[
\left[\begin{array}{c} c_{1} + c_{2} - 1 \\ -3 c_{1} + c_{2} - 1 \end{array}\right] = \left[\begin{array}{l} 0 \\ 2 \end{array}\right]
\]
Solve the system of equations:
\(c_{1} + c_{2} = 1\)
\(-3 c_{1} + c_{2} = 3\)
Subtracting the first equation from the second, we get \(-4 c_{1} = 2\), so \(c_{1} = -\frac{1}{2}\).
Then \(c_{2} = 1 - c_{1} = 1 - (-\frac{1}{2}) = \frac{3}{2}\).
\(\boxed{\left[\begin{array}{c} -\frac{1}{2} t^{2} + \frac{3}{2} t^{6} - t \\ \frac{3}{2} t^{2} + \frac{3}{2} t^{6} - t \end{array}\right]}\)
The solution to the system of differential equations is:
\(\boxed{\left[\begin{array}{c} -\frac{1}{2} t^{2} + \frac{3}{2} t^{6} - t \\ \frac{3}{2} t^{2} + \frac{3}{2} t^{6} - t \end{array}\right]}\)