Questions: Graph the following function on the axes provided. f(x) = - -x-3 for x<1 - 2 for x=1 - 6x-7 for x>1

Graph the following function on the axes provided.

f(x) = 
- -x-3 for x<1
- 2 for x=1
- 6x-7 for x>1
Transcript text: Graph the following function on the axes provided. \[ f(x)=\left\{\begin{array}{lll} -x-3 & \text { for } & x<1 \\ 2 & \text { for } & x=1 \\ 6 x-7 & \text { for } & x>1 \end{array}\right. \] Line Closed Circle Open Circle Click and drag to make a line. Click the line to, delete it. Click on an endpoint of a line to change it.
failed

Solution

failed
failed

Solution Steps

Step 1: Graph the function for \( x < 1 \)

For \( x < 1 \), the function is \( f(x) = -x - 3 \). This is a linear function with a slope of -1 and a y-intercept of -3.

To graph this:

  • Start at the y-intercept (0, -3).
  • Use the slope to find another point. For example, from (0, -3), move down 1 unit and right 1 unit to get to the point (1, -4).
  • Since this part of the function is only valid for \( x < 1 \), draw the line up to but not including \( x = 1 \). Use an open circle at \( x = 1 \) to indicate that this point is not included.
Step 2: Plot the point for \( x = 1 \)

For \( x = 1 \), the function is \( f(x) = 2 \).

To graph this:

  • Plot a closed circle at the point (1, 2) to indicate that this point is included in the function.
Step 3: Graph the function for \( x > 1 \)

For \( x > 1 \), the function is \( f(x) = 6x - 7 \). This is a linear function with a slope of 6 and a y-intercept of -7.

To graph this:

  • Start at the y-intercept (0, -7).
  • Use the slope to find another point. For example, from (0, -7), move up 6 units and right 1 unit to get to the point (1, -1).
  • Since this part of the function is only valid for \( x > 1 \), draw the line starting just after \( x = 1 \). Use an open circle at \( x = 1 \) to indicate that this point is not included.

Final Answer

The graph of the piecewise function \( f(x) \) is as follows:

  • A line segment from \( x = -\infty \) to \( x = 1 \) (not including 1) with the equation \( f(x) = -x - 3 \).
  • A closed circle at the point (1, 2).
  • A line segment from \( x = 1 \) (not including 1) to \( x = \infty \) with the equation \( f(x) = 6x - 7 \).
Was this solution helpful?
failed
Unhelpful
failed
Helpful