Questions: How many moles of C6H12O6 are contained in each volume of aqueous C6H12O6 solution? Be sure each of your answer entries has the correct number of significant figures. Part 1 of 2 8.3 L of a 0.52 M solution Part 2 of 2 520 mL of a 0.48 M solution

How many moles of C6H12O6 are contained in each volume of aqueous C6H12O6 solution? Be sure each of your answer entries has the correct number of significant figures.

Part 1 of 2
8.3 L of a 0.52 M solution

Part 2 of 2

520 mL of a 0.48 M solution
Transcript text: How many moles of $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$ are contained in each volume of aqueous $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}$ solution? Be sure each of your answer entries has the correct number of significant figures. Part 1 of 2 8.3 L of a 0.52 M solution Part 2 of 2 520 mL of a 0.48 M solution
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Solution

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Solution Steps

Step 1: Understand the Problem

We need to calculate the number of moles of \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\) in given volumes of solutions with known molarity. Molarity (M) is defined as moles of solute per liter of solution.

Step 2: Calculate Moles for Part 1
  • Given: 8.3 L of a 0.52 M solution.
  • Formula: Moles = Molarity \(\times\) Volume (in liters).
  • Calculation: \[ \text{Moles} = 0.52 \, \text{M} \times 8.3 \, \text{L} = 4.316 \, \text{mol} \]
  • Significant Figures: The answer should have two significant figures (based on the given data), so it is 4.3 mol.
Step 3: Calculate Moles for Part 2
  • Given: 520 mL of a 0.48 M solution.
  • Convert Volume: 520 mL = 0.520 L.
  • Formula: Moles = Molarity \(\times\) Volume (in liters).
  • Calculation: \[ \text{Moles} = 0.48 \, \text{M} \times 0.520 \, \text{L} = 0.2496 \, \text{mol} \]
  • Significant Figures: The answer should have three significant figures (based on the given data), so it is 0.250 mol.

Final Answer

For Part 1: \( \boxed{4.3 \, \text{mol}} \)
For Part 2: \( \boxed{0.250 \, \text{mol}} \)

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