Questions: Since an instant replay system for tennis was introduced at a major tournament, men challenged 1422 referee calls, with the result that 411 of the calls were overturned. Women challenged 768 referee calls, and 224 of the calls were overturned. Use a 0.05 significance level to test the claim that men and women have equal success in challenging. calls. Complete parts (a) through (c) below.
a. Test the claim using a hypothesis test.
Consider the first sample to be the sample of male tennis players who challenged referee calls and the second sample to be the sample of female tennis players who challenged referee calls. What are the null and alternative hypotheses for the hypothesis test?
A. H0 · p1 ≥ p2 B. H0: p1=p2 C. H0: p1=p2 H1: p1 ≠ p2 H3: p1 ≠ p2 H1: p1<p2
D. H0: P1=P2 E. H0: p1 ≠ p2 F. H0: p1 ≤ p2 H1: P1>P2 H1: p1=p2 H1: p1 ≠ p2
Transcript text: Since an instant replay system for tennis was introduced at a major tournament, men challenged 1422 referee calls, with the result that 411 of the calls were overturned. Women challenged 768 referee calls, and 224 of the calls were overturned. Use a 0.05 significance level to test the claim that men and women have equal success in challenging. calls. Complete parts (a) through (c) below.
a. Test the claim using a hypothesis test.
Consider the first sample to be the sample of male tennis players who challenged referee calls and the second sample to be the sample of female tennis players who challenged referee calls. What are the null and alternative hypotheses for the hypothesis test?
A. $H_{0} \cdot p_{1} \geq p_{2}$ B. $H_{0}: p_{1}=p_{2}$ C. $\mathrm{H}_{0}: \mathrm{p}_{1}=\mathrm{p}_{2}$ $H_{1}: p_{1} \neq p_{2}$ $H_{3}: p_{1} \neq p_{2}$ $H_{1}: p_{1}P_{2}$ $H_{1}: p_{1}=p_{2}$ $H_{1}: p_{1} \neq p_{2}$
Solution
Solution Steps
Step 1: Define Hypotheses
We define the null and alternative hypotheses as follows:
Null Hypothesis: \( H_0: p_1 = p_2 \) (men and women have equal success in challenging calls)
Alternative Hypothesis: \( H_1: p_1 \neq p_2 \) (men and women do not have equal success in challenging calls)
Step 2: Calculate Test Statistic
The test statistic \( Z \) is calculated using the formula:
\[
Z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1 - p_0)}{n}}}
\]
where:
\( p_0 = \frac{224}{768} \approx 0.2917 \) (hypothesized population proportion for women)
\( n = 1422 \) (sample size for men)
Substituting the values, we find:
\[
Z \approx -0.2188
\]
Step 3: Calculate P-value
The P-value associated with the test statistic \( Z = -0.2188 \) is calculated to be:
\[
\text{P-value} \approx 0.8268
\]
Step 4: Determine Critical Region
For a significance level of \( \alpha = 0.05 \) in a two-tailed test, the critical region is defined as:
\[
Z < -1.96 \quad \text{or} \quad Z > 1.96
\]
Step 5: Make a Decision
Since the calculated P-value \( 0.8268 \) is greater than \( 0.05 \), we fail to reject the null hypothesis. This indicates that there is no significant difference in success rates between men and women in challenging calls.
Final Answer
The conclusion is that there is no significant difference in success rates between men and women in challenging calls. Thus, we have:
\[
\boxed{\text{Fail to reject } H_0}
\]