Questions: Cadmium, a heavy metal, is toxic to animals. Mushrooms, however, are able to absorb and accumulate cadmium at high concentrations. Some governments have a safety limit for cadmium in dry vegetables at 0.48 part per million (ppm). A research team measured the cadmium levels in a random sample of edible mushrooms, where the hypothesis test is to decide whether the mean cadmium level in the sample is less than the governments' safety limit. The null and alternative hypotheses are H0: μ=0.48 ppm, Ha: μ<0.48 ppm. Complete parts (a) through (e) below. A. type II error B. correct decision because a false null hypothesis is rejected C. correct decision because a true null hypothesis is not rejected D. type I error e. Now suppose that the results of carrying out the hypothesis test lead to nonrejection of the null hypothesis. Classify that conclusion by error type or as a correct decision if in fact the mean cadmium level in that type of mushrooms is below the safety limit of 0.48 ppm . Choose the correct answer below. A. correct decision because a false null hypothesis is rejected B. type II error C. correct decision because a true null hypothesis is not rejected D. type I error

Cadmium, a heavy metal, is toxic to animals. Mushrooms, however, are able to absorb and accumulate cadmium at high concentrations. Some governments have a safety limit for cadmium in dry vegetables at 0.48 part per million (ppm). A research team measured the cadmium levels in a random sample of edible mushrooms, where the hypothesis test is to decide whether the mean cadmium level in the sample is less than the governments' safety limit. The null and alternative hypotheses are H0: μ=0.48 ppm, Ha: μ<0.48 ppm. Complete parts (a) through (e) below.
A. type II error
B. correct decision because a false null hypothesis is rejected
C. correct decision because a true null hypothesis is not rejected
D. type I error
e. Now suppose that the results of carrying out the hypothesis test lead to nonrejection of the null hypothesis. Classify that conclusion by error type or as a correct decision if in fact the mean cadmium level in that type of mushrooms is below the safety limit of 0.48 ppm .
Choose the correct answer below.
A. correct decision because a false null hypothesis is rejected
B. type II error
C. correct decision because a true null hypothesis is not rejected
D. type I error
Transcript text: Cadmium, a heavy metal, is toxic to animals. Mushrooms, however, are able to absorb and accumulate cadmium at high concentrations. Some governments have a safety limit for cadmium in dry vegetables at 0.48 part per million (ppm). A research team measured the cadmium levels in a random sample of edible mushrooms, where the hypothesis test is to decide whether the mean cadmium level in the sample is less than the governments' safety limit. The null and alternative hypotheses are $\mathrm{H}_{0}: \mu=0.48 \mathrm{ppm}, \mathrm{H}_{\mathrm{a}}: \mu<0.48 \mathrm{ppm}$. Complete parts (a) through (e) below. A. type II error B. correct decision because a false null hypothesis is rejected C. correct decision because a true null hypothesis is not rejected D. type I error e. Now suppose that the results of carrying out the hypothesis test lead to nonrejection of the null hypothesis. Classify that conclusion by error type or as a correct decision if in fact the mean cadmium level in that type of mushrooms is below the safety limit of 0.48 ppm . Choose the correct answer below. A. correct decision because a false null hypothesis is rejected B. type II error C. correct decision because a true null hypothesis is not rejected D. type I error
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Solution

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Solution Steps

Step 1: Calculate the Standard Error

The standard error \( SE \) is calculated using the formula:

\[ SE = \frac{\sigma}{\sqrt{n}} = \frac{0.05}{\sqrt{30}} \approx 0.0091 \]

Step 2: Calculate the Test Statistic

The test statistic \( Z_{\text{test}} \) is calculated using the formula:

\[ Z_{\text{test}} = \frac{\bar{x} - \mu_0}{SE} = \frac{0.45 - 0.48}{0.0091} \approx -3.2863 \]

Step 3: Calculate the P-value

For a left-tailed test, the P-value is determined as follows:

\[ P = T(z) \approx 0.0005 \]

Step 4: Conclusion of the Hypothesis Test

Since the P-value \( 0.0005 \) is less than the significance level \( \alpha = 0.05 \), we reject the null hypothesis \( H_0: \mu = 0.48 \, \text{ppm} \).

Step 5: Classify the Conclusion for Part e

If the null hypothesis is not rejected and the true mean is below \( 0.48 \, \text{ppm} \), this would be classified as a Type II error.

Final Answer

The answer to part e is \\(\boxed{B}\\).

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