Questions: Let f(x)=sin x and h(x)=2 x. Find the value of (f ∘ h)(π/6).
Transcript text: Let $f(x)=\sin x$ and $h(x)=2 x$. Find the value of $(f \circ h)\left(\frac{\pi}{6}\right)$.
Solution
Solution Steps
To solve for \((f \circ h)\left(\frac{\pi}{6}\right)\), we need to first find \(h\left(\frac{\pi}{6}\right)\) and then apply the function \(f\) to the result. Specifically, we will:
Use the result from step 1 as the input to \(f(x) = \sin x\).
Step 1: Compute \( h\left(\frac{\pi}{6}\right) \)
First, we need to evaluate the function \( h(x) = 2x \) at \( x = \frac{\pi}{6} \):
\[
h\left(\frac{\pi}{6}\right) = 2 \cdot \frac{\pi}{6} = \frac{\pi}{3}
\]
Next, we use the result from Step 1 as the input to the function \( f(x) = \sin x \):
\[
f\left(h\left(\frac{\pi}{6}\right)\right) = f\left(\frac{\pi}{3}\right) = \sin\left(\frac{\pi}{3}\right)
\]