Questions: Coordinate Geometry Graphing a line given its equation in slope-intercept form DEVRICK Graph the line. y = -(1/3)x + 5

Solution Steps

The equation is in slope-intercept form, \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept. In this case, \(m = -\frac{1}{3}\) and \(b = 5\).

The y-intercept is the point where the line crosses the y-axis. Since \(b = 5\), the y-intercept is \((0, 5)\). Plot this point on the graph.

The slope is \(-\frac{1}{3}\), which means that for every 3 units we move to the right along the x-axis, we move 1 unit down along the y-axis. Starting from the y-intercept \((0, 5)\), move 3 units to the right and 1 unit down to reach the point \((3, 4)\). Plot this point.

Draw a straight line through the points \((0, 5)\) and \((3, 4)\). This line represents the graph of the equation \(y = -\frac{1}{3}x + 5\).

Final Answer