Questions: Calculate the energy required for the electronic transition from n=3 to n=5 in the hydrogen atom.

Solution Steps

The energy levels of a hydrogen atom are given by the formula:

$$E_n = -\frac{13.6 \, \text{eV}}{n^2}$$

where $n$ is the principal quantum number, and 13.6 eV is the ionization energy of hydrogen.

First, calculate the energy for $n = 3$:

$$E_3 = -\frac{13.6 \, \text{eV}}{3^2} = -\frac{13.6 \, \text{eV}}{9} = -1.5111 \, \text{eV}$$

Next, calculate the energy for $n = 5$:

$$E_5 = -\frac{13.6 \, \text{eV}}{5^2} = -\frac{13.6 \, \text{eV}}{25} = -0.5440 \, \text{eV}$$

The energy required for the transition from $n = 3$ to $n = 5$ is the difference between the energies of these two levels:

$$\Delta E = E_5 - E_3 = (-0.5440 \, \text{eV}) - (-1.5111 \, \text{eV}) = 0.9671 \, \text{eV}$$

Final Answer