The argument of the logarithm is given by \(b + mx\). In this case, it is \( 5 + 2x\).
For the logarithm to be defined, its argument must be greater than zero. Therefore, we set \( 5 + 2x > 0\).
Since \(m > 0\), the solution to the inequality \( 5 + 2x > 0\) is \(x > -2.5\).
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