Questions: Suppose that the function (g) is defined, for all real numbers, as follows.
[g(x)=leftbeginarrayll frac12 x-1 text if x neq-2 1 text if x=-2 endarrayright.]
Find (g(-5), g(-2)), and (g(5)).
[ beginarrayc g(-5)=square g(-2)=square g(5)=square endarray ]
Transcript text: Suppose that the function $g$ is defined, for all real numbers, as follows.
\[
g(x)=\left\{\begin{array}{ll}
\frac{1}{2} x-1 & \text { if } x \neq-2 \\
1 & \text { if } x=-2
\end{array}\right.
\]
Find $g(-5), g(-2)$, and $g(5)$.
\[
\begin{array}{c}
g(-5)=\square \\
g(-2)=\square \\
g(5)=\square
\end{array}
\]
Solution
Solution Steps
To find the values of the function \( g \) at specific points, we need to evaluate the piecewise function for each given input. For \( g(-5) \) and \( g(5) \), we use the expression \(\frac{1}{2}x - 1\) since these values are not equal to \(-2\). For \( g(-2) \), we use the value \(1\) as specified by the function definition for \( x = -2 \).
Step 1: Evaluate \( g(-5) \)
To find \( g(-5) \), we use the piecewise definition of the function:
\[
g(-5) = \frac{1}{2}(-5) - 1 = -\frac{5}{2} - 1 = -\frac{5}{2} - \frac{2}{2} = -\frac{7}{2} = -3.5
\]
Step 2: Evaluate \( g(-2) \)
For \( g(-2) \), we directly use the value defined in the piecewise function:
\[
g(-2) = 1
\]
Step 3: Evaluate \( g(5) \)
To find \( g(5) \), we again use the piecewise definition:
\[
g(5) = \frac{1}{2}(5) - 1 = \frac{5}{2} - 1 = \frac{5}{2} - \frac{2}{2} = \frac{3}{2} = 1.5
\]