Questions: 10) Disney The histogram summarizes wait times for the Splash Mountain ride at Walt Disney World from Jan 2012 to Aug 2018. a) Estimate the median wait time b) Mark up the histogram to demonstrate why your estimate is reasonable. Frequency 1000 800 600 400 200 0 0 20 40 60 80 Wait Time (Minutes)

 10) Disney The histogram summarizes wait times for the Splash Mountain ride at Walt Disney World from Jan 2012 to Aug 2018.
a) Estimate the median wait time
b) Mark up the histogram to demonstrate why your estimate is reasonable.

Frequency

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Wait Time (Minutes)
Transcript text: 10) Disney The histogram summarizes wait times for the Splash Mountain ride at Walt Disney World from Jan 2012 to Aug 2018. a) Estimate the median wait time b) Mark up the histogram to demonstrate why your estimate is reasonable. Frequency 1000 800 600 400 200 0 0 20 40 60 80 Wait Time (Minutes)
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Solution

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Solution Steps

Step 1: Understand the Problem

The problem requires estimating the median wait time for the Splash Mountain ride at Walt Disney World from January 2012 to August 2018 using the provided histogram.

Step 2: Identify the Median

The median is the middle value of a data set. In a histogram, the median wait time is the point where half of the data lies below and half lies above.

Step 3: Analyze the Histogram

The histogram shows the frequency of wait times in different intervals. To find the median, we need to determine the cumulative frequency and find the interval where the cumulative frequency reaches half of the total data points.

Step 4: Calculate the Total Frequency

Sum the frequencies of all intervals to get the total number of data points.

Step 5: Determine the Median Interval

Find the interval where the cumulative frequency reaches half of the total frequency.

Step 6: Estimate the Median

Estimate the median wait time based on the interval identified in the previous step.

Final Answer

The median wait time is approximately 10-20 minutes. This estimate is reasonable because the cumulative frequency reaches half of the total frequency within this interval.

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