Questions: Solve each system of inequ
x-y ≤ 2
x+2y ≥ 1
Transcript text: Solve each system of inequ
\[
\begin{array}{l}
x-y \leq 2 \\
x+2 y \geq 1
\end{array}
\]
Solution
Solution Steps
To solve the system of inequalities, we need to find the region in the coordinate plane that satisfies both inequalities simultaneously. We can do this by plotting the boundary lines of each inequality and then determining the region that satisfies both conditions.
Step 1: Define the Inequalities
We start with the system of inequalities:
\[
\begin{array}{l}
x - y \leq 2 \\
x + 2y \geq 1
\end{array}
\]
Step 2: Convert Inequalities to Equations
Convert the inequalities to equations to find the boundary lines:
\[
\begin{array}{l}
x - y = 2 \\
x + 2y = 1
\end{array}
\]
Step 3: Solve for \( y \) in Terms of \( x \)
Solve each equation for \( y \):
\[
\begin{array}{l}
y = x - 2 \\
y = \frac{1 - x}{2}
\end{array}
\]
Step 4: Plot the Boundary Lines
Plot the lines \( y = x - 2 \) and \( y = \frac{1 - x}{2} \) to visualize the boundaries.
Step 5: Determine the Feasible Region
Identify the region that satisfies both inequalities:
For \( x - y \leq 2 \), the region is below the line \( y = x - 2 \).
For \( x + 2y \geq 1 \), the region is above the line \( y = \frac{1 - x}{2} \).
The feasible region is the intersection of these two regions.
Final Answer
\[
\boxed{y \leq x - 2 \text{ and } y \geq \frac{1 - x}{2}}
\]