Questions: For her phone service, Leila pays a monthly fee of 30, and she pays an additional 0.06 per minute of use. The least she has been charged in a month is 109.02. What are the possible numbers of minutes she has used her phone in a month? Use m for the number of minutes, and solve your inequality for m.

For her phone service, Leila pays a monthly fee of 30, and she pays an additional 0.06 per minute of use. The least she has been charged in a month is 109.02.

What are the possible numbers of minutes she has used her phone in a month? Use m for the number of minutes, and solve your inequality for m.
Transcript text: For her phone service, Leila pays a monthly fee of $\$ 30$, and she pays an additional $\$ 0.06$ per minute of use. The least she has been charged in a month is \$109.02. What are the possible numbers of minutes she has used her phone in a month? Use $m$ for the number of minutes, and solve your inequality for $m$.
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Solution

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Solution Steps

Step 1: Define the inequality

Leila's total monthly cost consists of a fixed fee of \$30 plus \$0.06 per minute of use. The least she has been charged is \$109.02. This can be expressed as: \[ 30 + 0.06m \geq 109.02 \]

Step 2: Subtract the fixed fee

Subtract the fixed fee of \$30 from both sides of the inequality to isolate the term with \( m \): \[ 0.06m \geq 109.02 - 30 \] \[ 0.06m \geq 79.02 \]

Step 3: Solve for \( m \)

Divide both sides of the inequality by \$0.06 to solve for \( m \): \[ m \geq \frac{79.02}{0.06} \] \[ m \geq 1317 \]

Final Answer

\(\boxed{m \geq 1317}\)

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