The given truth table includes two propositions \( p \) and \( q \).
The table shows the truth values for \( p \), \( q \), \( \neg p \), \( \neg q \), \( p \land q \), \( p \lor q \), \( \neg p \lor \neg q \), and \( (p \land q) \rightarrow \neg (p \lor q) \).
Step 2: Analyze the truth table
The truth table provides the truth values for each combination of \( p \) and \( q \):
\( p \) and \( q \) both true (T, T)
\( p \) true and \( q \) false (T, F)
\( p \) false and \( q \) true (F, T)
\( p \) and \( q \) both false (F, F)
Step 3: Determine the validity of the argument
To determine if the argument is valid, we need to check if the conditional statement \( (p \land q) \rightarrow \neg (p \lor q) \) is true in all cases.
From the truth table:
When \( p \) and \( q \) are both true, \( (p \land q) \) is true and \( \neg (p \lor q) \) is false, making the conditional false.
In all other cases, the conditional is true.
Final Answer
The argument is not valid because the conditional statement \( (p \land q) \rightarrow \neg (p \lor q) \) is not true in all cases.