Questions: What is the total number of electrons needed in order to build the Lewis structure for N2O?

Solution Steps

To find the total number of electrons needed to build the Lewis structure for \( \mathrm{N}_2\mathrm{O} \), we first need to determine the number of valence electrons for each atom in the molecule.

• Nitrogen (N) has 5 valence electrons.
• Oxygen (O) has 6 valence electrons.

Next, we calculate the total number of valence electrons by summing the valence electrons of all the atoms in the molecule.

\[ \text{Total valence electrons} = 2 \times (\text{valence electrons of N}) + (\text{valence electrons of O}) \]

\[ \text{Total valence electrons} = 2 \times 5 + 6 = 10 + 6 = 16 \]

Final Answer