Questions: A set of data values is normally distributed with a mean of 60 and a standard deviation of 8. Give the standard score and approximate percentile for a data value of 58.
The standard score for 58 is z=
Transcript text: A set of data values is normally distributed with a mean of 60 and a standard deviation of 8. Give the standard score and approximate percentile for a data value of 58.
The standard score for 58 is $z=$ $\square$
(Do not round until the final answer. Then round to the nearest hundredth as needed.)
Solution
Solution Steps
To find the standard score (z-score) for a data value in a normally distributed set, we use the formula:
\[ z = \frac{(X - \mu)}{\sigma} \]
where \( X \) is the data value, \( \mu \) is the mean, and \( \sigma \) is the standard deviation. Once we have the z-score, we can use the provided table to find the approximate percentile.
Step 1: Calculate the z-score
To find the standard score (z-score) for a data value in a normally distributed set, we use the formula:
\[ z = \frac{X - \mu}{\sigma} \]
where:
\( X = 58 \) (data value)
\( \mu = 60 \) (mean)
\( \sigma = 8 \) (standard deviation)
Substituting the values, we get:
\[ z = \frac{58 - 60}{8} = \frac{-2}{8} = -0.25 \]
Step 2: Determine the approximate percentile
Using the provided table of standard scores and percentiles, we find the percentile corresponding to \( z = -0.25 \). According to the table, the percentile for \( z = -0.25 \) is approximately \( 40.13 \).
Final Answer
The standard score (z-score) for a data value of 58 is:
\[ \boxed{z = -0.25} \]
The approximate percentile for a z-score of -0.25 is:
\[ \boxed{40.13} \]