Questions: A set of data values is normally distributed with a mean of 60 and a standard deviation of 8. Give the standard score and approximate percentile for a data value of 58. The standard score for 58 is z=

A set of data values is normally distributed with a mean of 60 and a standard deviation of 8. Give the standard score and approximate percentile for a data value of 58.

The standard score for 58 is z=
Transcript text: A set of data values is normally distributed with a mean of 60 and a standard deviation of 8. Give the standard score and approximate percentile for a data value of 58. The standard score for 58 is $z=$ $\square$ (Do not round until the final answer. Then round to the nearest hundredth as needed.)
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Solution

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Solution Steps

To find the standard score (z-score) for a data value in a normally distributed set, we use the formula: \[ z = \frac{(X - \mu)}{\sigma} \] where \( X \) is the data value, \( \mu \) is the mean, and \( \sigma \) is the standard deviation. Once we have the z-score, we can use the provided table to find the approximate percentile.

Step 1: Calculate the z-score

To find the standard score (z-score) for a data value in a normally distributed set, we use the formula: \[ z = \frac{X - \mu}{\sigma} \] where:

  • \( X = 58 \) (data value)
  • \( \mu = 60 \) (mean)
  • \( \sigma = 8 \) (standard deviation)

Substituting the values, we get: \[ z = \frac{58 - 60}{8} = \frac{-2}{8} = -0.25 \]

Step 2: Determine the approximate percentile

Using the provided table of standard scores and percentiles, we find the percentile corresponding to \( z = -0.25 \). According to the table, the percentile for \( z = -0.25 \) is approximately \( 40.13 \).

Final Answer

The standard score (z-score) for a data value of 58 is: \[ \boxed{z = -0.25} \]

The approximate percentile for a z-score of -0.25 is: \[ \boxed{40.13} \]

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