Questions: Find the population standard deviation for 2019. Round the answer to at least two decimal places.
In 2019, the population standard deviation, in thousands of dollars, was .
Transcript text: Find the population standard deviation for 2019. Round the answer to at least two decimal places.
In 2019, the population standard deviation, in thousands of dollars, was $\square$ . $\square$
Solution
Solution Steps
To find the population standard deviation for 2019, we need to calculate the square root of the average of the squared deviations from the mean. This involves the following steps:
Calculate the mean of the data set.
Subtract the mean from each data point and square the result.
Find the average of these squared differences.
Take the square root of this average to get the population standard deviation.
To solve the problem of finding the population standard deviation for 2019, we need to follow these steps:
Step 1: Understand the Problem
The problem asks us to find the population standard deviation for a given dataset from 2019. However, the dataset is not provided in the question. For the sake of this example, let's assume we have a dataset of values representing thousands of dollars: \( x_1, x_2, \ldots, x_n \).
Step 2: Calculate the Mean
The population mean (\(\mu\)) is calculated as follows:
\[
\mu = \frac{1}{n} \sum_{i=1}^{n} x_i
\]
where \( n \) is the number of data points.
Step 3: Calculate the Variance
The population variance (\(\sigma^2\)) is calculated using the formula:
\[
\sigma^2 = \frac{1}{n} \sum_{i=1}^{n} (x_i - \mu)^2
\]
Step 4: Calculate the Standard Deviation
The population standard deviation (\(\sigma\)) is the square root of the variance:
\[
\sigma = \sqrt{\sigma^2}
\]
Step 5: Round the Result
Round the standard deviation to at least two decimal places.
Final Answer
Since the dataset is not provided, we cannot compute a numerical answer. However, the process to find the population standard deviation is outlined above. If you have the dataset, you can apply these steps to find the standard deviation.