Questions: √6 45° √2 x 3

√6

45°

√2

x

3
Transcript text: $\sqrt{6}$ $45°$ $\sqrt{2}$ $x$ 3
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Solution

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Find xx. Use the 45-45-90 triangle rule. In a 45-45-90 triangle, the two legs are congruent, and the hypotenuse is 2\sqrt{2} times the length of each leg. In this case, the length of the leg is 6\sqrt{6}, and the hypotenuse is xx. So, x=6×2=12=23x = \sqrt{6} \times \sqrt{2} = \sqrt{12} = 2\sqrt{3}. x=23\boxed{x = 2\sqrt{3}}

x=23\boxed{x = 2\sqrt{3}}

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