Questions: √6 45° √2 x 3

√6 45° √2 x 3
Transcript text: $\sqrt{6}$ $45°$ $\sqrt{2}$ $x$ 3
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Solution

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Find \(x\). Use the 45-45-90 triangle rule. In a 45-45-90 triangle, the two legs are congruent, and the hypotenuse is \(\sqrt{2}\) times the length of each leg. In this case, the length of the leg is \(\sqrt{6}\), and the hypotenuse is \(x\). So, \(x = \sqrt{6} \times \sqrt{2} = \sqrt{12} = 2\sqrt{3}\). \(\boxed{x = 2\sqrt{3}}\)

\(\boxed{x = 2\sqrt{3}}\)

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