Questions: A population numbers 12,000 organisms initially and grows by 16.1% each year. Suppose P represents population and t represents the number of years of growth. An exponential model for the population can be written in the form P = a b^t, where P = □

A population numbers 12,000 organisms initially and grows by 16.1% each year. Suppose P represents population and t represents the number of years of growth. An exponential model for the population can be written in the form P = a b^t, where
P = □
Transcript text: A population numbers 12,000 organisms initially and grows by $16.1 \%$ each year. Suppose $P$ represents population and $t$ represents the number of years of growth. An exponential model for the population can be written in the form $P=a b^{t}$, where \[ P=\square \] Question Help: Video 1 Video 2
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Solution

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Solution Steps

Step 1: Identify the Initial Population and Growth Rate

The problem states that the initial population is 12,000 organisms and the growth rate is \(16.1\%\) per year.

Step 2: Convert the Growth Rate to a Decimal

To use the growth rate in the exponential model, we need to convert the percentage to a decimal. The growth rate of \(16.1\%\) is equivalent to \(0.161\) in decimal form.

Step 3: Determine the Base of the Exponential Model

The base \(b\) in the exponential model \(P = a b^t\) represents the growth factor. Since the population grows by \(16.1\%\) each year, the growth factor is \(1 + 0.161 = 1.161\).

Step 4: Write the Exponential Model

Using the initial population \(a = 12,000\) and the growth factor \(b = 1.161\), the exponential model for the population is:

\[ P = 12,000 \times 1.161^t \]

Final Answer

\[ \boxed{P = 12,000 \times 1.161^t} \]

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