Questions: Solve the equation for the positive value of x. x^2 + y^2 = 25, where y=4

Solve the equation for the positive value of x.
x^2 + y^2 = 25, where y=4
Transcript text: Solve the equation for the positive value of $x$. \[ x^{2}+y^{2}=25, \text { where } y=4 \]
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Solution

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Solution Steps

Step 1: Substitute the Value of \( y \)

Given the equation:

\[ x^2 + y^2 = 25 \]

and the value \( y = 4 \), substitute \( y \) into the equation:

\[ x^2 + 4^2 = 25 \]

Step 2: Simplify the Equation

Calculate \( 4^2 \):

\[ x^2 + 16 = 25 \]

Subtract 16 from both sides:

\[ x^2 = 25 - 16 \]

\[ x^2 = 9 \]

Step 3: Solve for \( x \)

Take the square root of both sides to solve for \( x \):

\[ x = \sqrt{9} \]

Since we are looking for the positive value of \( x \):

\[ x = 3 \]

Final Answer

The positive value of \( x \) is \(\boxed{3}\).

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