Questions: (a) How many atoms of helium gas fill a spherical balloon of diameter 31.0 cm at 17.0°C and 1.00 atm? atoms (b) What is the average kinetic energy of the helium atoms? J (c) What is the rms speed of the helium atoms? km / s

(a) How many atoms of helium gas fill a spherical balloon of diameter 31.0 cm at 17.0°C and 1.00 atm? atoms
(b) What is the average kinetic energy of the helium atoms? 
J
(c) What is the rms speed of the helium atoms? 
km / s
Transcript text: (a) How many atoms of helium gas fill a spherical balloon of diameter 31.0 cm at $17.0^{\circ} \mathrm{C}$ and 1.00 atm ? $\square$ atoms (b) What is the average kinetic energy of the helium atoms? $\square$ J (c) What is the rms speed of the helium atoms? $\square$ $\mathrm{km} / \mathrm{s}$ Submit Answer
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Solution

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Solution Steps

Step 1: Calculate the Volume of the Balloon

The diameter of the spherical balloon is given as 31.0 cm. First, we convert this to meters:

\[ \text{Diameter} = 31.0 \, \text{cm} = 0.310 \, \text{m} \]

The radius \( r \) is half of the diameter:

\[ r = \frac{0.310}{2} = 0.155 \, \text{m} \]

The volume \( V \) of a sphere is given by:

\[ V = \frac{4}{3} \pi r^3 \]

Substituting the radius:

\[ V = \frac{4}{3} \pi (0.155)^3 \approx 0.0156 \, \text{m}^3 \]

Step 2: Use the Ideal Gas Law to Find the Number of Moles

The ideal gas law is given by:

\[ PV = nRT \]

Where:

  • \( P = 1.00 \, \text{atm} = 101325 \, \text{Pa} \)
  • \( V = 0.0156 \, \text{m}^3 \)
  • \( R = 8.314 \, \text{J/mol} \cdot \text{K} \)
  • \( T = 17.0^{\circ} \text{C} = 290.15 \, \text{K} \)

Rearranging for \( n \):

\[ n = \frac{PV}{RT} = \frac{101325 \times 0.0156}{8.314 \times 290.15} \approx 0.654 \, \text{mol} \]

Step 3: Calculate the Number of Atoms

The number of atoms is given by:

\[ \text{Number of atoms} = n \times N_A \]

Where \( N_A = 6.022 \times 10^{23} \, \text{atoms/mol} \):

\[ \text{Number of atoms} = 0.654 \times 6.022 \times 10^{23} \approx 3.94 \times 10^{23} \, \text{atoms} \]

Step 4: Calculate the Average Kinetic Energy

The average kinetic energy per atom is given by:

\[ \text{Average kinetic energy} = \frac{3}{2} k_B T \]

Where \( k_B = 1.38 \times 10^{-23} \, \text{J/K} \):

\[ \text{Average kinetic energy} = \frac{3}{2} \times 1.38 \times 10^{-23} \times 290.15 \approx 6.00 \times 10^{-21} \, \text{J} \]

Step 5: Calculate the RMS Speed

The root-mean-square (rms) speed is given by:

\[ v_{\text{rms}} = \sqrt{\frac{3k_B T}{m}} \]

The molar mass of helium is \( 4.00 \, \text{g/mol} = 4.00 \times 10^{-3} \, \text{kg/mol} \), so the mass of one atom is:

\[ m = \frac{4.00 \times 10^{-3}}{6.022 \times 10^{23}} \approx 6.64 \times 10^{-27} \, \text{kg} \]

Substituting into the rms speed formula:

\[ v_{\text{rms}} = \sqrt{\frac{3 \times 1.38 \times 10^{-23} \times 290.15}{6.64 \times 10^{-27}}} \approx 1255 \, \text{m/s} = 1.255 \, \text{km/s} \]

Final Answer

(a) The number of atoms of helium gas is \(\boxed{3.94 \times 10^{23}}\).

(b) The average kinetic energy of the helium atoms is \(\boxed{6.00 \times 10^{-21} \, \text{J}}\).

(c) The rms speed of the helium atoms is \(\boxed{1.255 \, \text{km/s}}\).

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