Questions: Question 26 Consider the following linear programming problem: Minimize: 20 X+30 Y Subject to: 2 X+4 Y ≤ 800 6 X+3 Y ≥ 300 X, Y ≥ 0 What is the optimum solution to this problem (X, Y) ? a. (0,0) b. (50,0) c. (0,100) d. (400,0) e. None of these

Question 26

Consider the following linear programming problem:
Minimize: 20 X+30 Y
Subject to: 2 X+4 Y ≤ 800
6 X+3 Y ≥ 300
X, Y ≥ 0

What is the optimum solution to this problem (X, Y) ?
a. (0,0)
b. (50,0)
c. (0,100)
d. (400,0)
e. None of these
Transcript text: Question 26 Consider the following linear programming problem: \[ \begin{array}{ll} \text { Minimize: } & 20 X+30 Y \\ \text { Subject to: } & 2 X+4 Y \leq 800 \\ & 6 X+3 Y \geq 300 \\ & X, Y \geq 0 \end{array} \] What is the optimum solution to this problem $(X, Y)$ ? a. $(0,0)$ b. $(50,0)$ c. $(0,100)$ d. $(400,0)$ e. None of these
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Solution

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Solution Steps

Step 1: Define the Problem

We are tasked with minimizing the objective function \(20X + 30Y\) subject to the constraints:

  1. \(2X + 4Y \leq 800\)
  2. \(6X + 3Y \geq 300\)
  3. \(X, Y \geq 0\)
Step 2: Solve the Linear Programming Problem

By applying the linear programming method, we find the optimal values for \(X\) and \(Y\). The solution yields: \[ X = 50, \quad Y = 0 \]

Final Answer

The optimum solution to the linear programming problem is \(\boxed{(X = 50, Y = 0)}\).

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