Questions: Question 26
Consider the following linear programming problem:
Minimize: 20 X+30 Y
Subject to: 2 X+4 Y ≤ 800
6 X+3 Y ≥ 300
X, Y ≥ 0
What is the optimum solution to this problem (X, Y) ?
a. (0,0)
b. (50,0)
c. (0,100)
d. (400,0)
e. None of these
Transcript text: Question 26
Consider the following linear programming problem:
\[
\begin{array}{ll}
\text { Minimize: } & 20 X+30 Y \\
\text { Subject to: } & 2 X+4 Y \leq 800 \\
& 6 X+3 Y \geq 300 \\
& X, Y \geq 0
\end{array}
\]
What is the optimum solution to this problem $(X, Y)$ ?
a. $(0,0)$
b. $(50,0)$
c. $(0,100)$
d. $(400,0)$
e. None of these
Solution
Solution Steps
Step 1: Define the Problem
We are tasked with minimizing the objective function \(20X + 30Y\) subject to the constraints:
\(2X + 4Y \leq 800\)
\(6X + 3Y \geq 300\)
\(X, Y \geq 0\)
Step 2: Solve the Linear Programming Problem
By applying the linear programming method, we find the optimal values for \(X\) and \(Y\). The solution yields:
\[
X = 50, \quad Y = 0
\]
Final Answer
The optimum solution to the linear programming problem is \(\boxed{(X = 50, Y = 0)}\).