Questions: Calculate the standard score of the given X value, X=75.1, where μ=68.3 and σ=71.8. Round your answer to two decimal places.

Calculate the standard score of the given X value, X=75.1, where μ=68.3 and σ=71.8. Round your answer to two decimal places.
Transcript text: Calculate the standard score of the given $X$ value, $X=75.1$, where $\mu=68.3$ and $\sigma=71.8$. Round your answer to two decimal places.
failed

Solution

failed
failed

Solution Steps

Step 1: Given Values

We are given the following values:

  • \( X = 75.1 \)
  • \( \mu = 68.3 \)
  • \( \sigma = 71.8 \)
Step 2: Calculate the Z-score

The Z-score is calculated using the formula:

\[ z = \frac{X - \mu}{\sigma} \]

Substituting the given values:

\[ z = \frac{75.1 - 68.3}{71.8} \]

Calculating the numerator:

\[ 75.1 - 68.3 = 6.8 \]

Now substituting back into the Z-score formula:

\[ z = \frac{6.8}{71.8} \approx 0.0947 \]

Rounding to two decimal places, we find:

\[ z \approx 0.09 \]

Final Answer

The Z-score is \\(\boxed{0.09}\\).

Was this solution helpful?
failed
Unhelpful
failed
Helpful

Questions asked by other users

failedAnswered
Examine this piece of colonial propaganda. What is the logical argument being made by this illustration?
failedAnswered
Question 41 (2 points) Which muscle(s) can contract without the need for nervous stimulation? cardiac muscle smooth muscle skeletal muscle smooth and cardiac muscle Question 42 (2 points) Arrange the following list of biochemical events in the correct sequence. (1) An action potential is conducted deep into the muscle fiber by the T tubule. (2) Calcium ions bind to troponin. (3) The membranes of the sarcoplasmic reticulum become more permeable to calcium ions. (4) Calcium ions diffuse into the sarcoplasm around the myofibril. (5) The troponin-tropomyosin complex moves exposing active sites. 1,4,3,2,5 1,3,2,5,4 1,2,3,4,5 1,5,2,3,4 1,3,4,2,5
failedAnswered
The numbers of successes and the sample sizes for independent simple random samples from two populations are provided for a right-tailed test. Use a 90% confidence interval. Complete parts (a) through (d). x1=23, n1=90, x2=22, n2=100, alpha=0.05 Click here to view a table of areas under the standard normal curve for negative values of z. Click here to view a table of areas under the standard normal curve for positive values of z. Which of the following is the correct conclusion for the hypothesis test? A. At the 5% significance level, reject H0; the data provide sufficient evidence to accept Ha. B. At the 5% significance level, do not reject H0; the data do not provide sufficient evidence to accept Ha. C. At the 5% significance level, do not reject H0; the data provide sufficient evidence to accept Ha. D. At the 5% significance level, reject H0; the data do not provide sufficient evidence to accept Ha. E. Using the two-proportions z-procedures is not appropriate.
failedAnswered
Please submit a rough draft of your hypothesis test, including all aspects (see the template from class notes, or the "Inference Test" portion of the outline for the final paper). I will try to give feedback on this submission within 24 hours so that you can correct any errors or oversights before the final version. female mean =4.53 Variance =0.2481 s D=0.4981 male mean =4.7333 variance =2.0619 s D=1.436 t=-0.423 a=0.05 a=0.05 since t=0.423 is less than t
failedAnswered
A 6 inch personal pizza has 580 calories, with 240 of those from fat. A 14 inch pizza is cut into 8 slices. Estimate the number of calories in one slice of a 14 inch pizza. Round your answer to the nearest calorie.