Questions: N2^2=2.1767 times 10^-18 / 5.4471 times 10^-19

N2^2=2.1767 times 10^-18 / 5.4471 times 10^-19
Transcript text: $N_{2}^{2}=\frac{2.1767 \times 10^{-18}}{5.4471 \times 10^{-19}}$
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Solution

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Solution Steps

Step 1: Calculate the Division

We start by calculating the division of the two given values: \[ N_{2}^{2} = \frac{2.1767 \times 10^{-18}}{5.4471 \times 10^{-19}} = 3.9960713039966222 \]

Step 2: Take the Square Root

Next, we take the square root of the result from Step 1 to find \( N_2 \): \[ N_2 = \sqrt{3.9960713039966222} \]

Step 3: Present the Final Result

After calculating the square root, we find: \[ N_2 \approx 1.999017584714207 \]

Final Answer

\(\boxed{N_2 \approx 1.999}\)

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