Questions: There are 8 students in a reading group. Three of the students are classified as strong readers, three as average and two as weak readers. A researcher wants to work with 2 randomly selected students from this group. What is the probability that both of the students she selects are the same type of reader?
Transcript text: There are 8 students in a reading group. Three of the students are classified as strong readers, three as average and two as weak readers. A researcher wants to work with 2 randomly selected students from this group. What is the probability that both of the students she selects are the same type of reader?
Solution
Solution Steps
Step 1: Probability of Selecting Two Strong Readers
To find the probability that both selected students are strong readers, we use the hypergeometric distribution formula:
P(X=k)=(nN)(kK)(n−kN−K)
For strong readers, we have:
N=8 (total students)
K=3 (strong readers)
n=2 (students selected)
k=2 (strong readers selected)
Calculating this gives:
P(X=2)=(28)(23)(05)=0.1071
Step 2: Probability of Selecting Two Average Readers
Next, we calculate the probability that both selected students are average readers using the same formula:
For average readers, we have:
N=8
K=3 (average readers)
n=2
k=2
Calculating this gives:
P(X=2)=(28)(23)(05)=0.1071
Step 3: Probability of Selecting Two Weak Readers
Now, we find the probability that both selected students are weak readers:
For weak readers, we have:
N=8
K=2 (weak readers)
n=2
k=2
Calculating this gives:
P(X=2)=(28)(22)(06)=0.0357
Step 4: Total Probability of Selecting the Same Type of Reader
Finally, we sum the probabilities of selecting two students of the same type: