Questions: Let f(x) = (x^2 - 1) / (x - 1) (a) Make tables of the values of f at values of x that approach x0 = -1 from above and below. Then estimate the limit as x approaches -1 of f(x). (b) Support your conclusion in part (a) by graphing f near x0 = -1 and using Zoom and Trace to estimate y-values on the graph as x approaches -1. (c) Find the limit as x approaches -1 of (x^2 - 1) / (x - 1) algebraically. (a) Complete the table given below.

Let f(x) = (x^2 - 1) / (x - 1)
(a) Make tables of the values of f at values of x that approach x0 = -1 from above and below. Then estimate the limit as x approaches -1 of f(x).
(b) Support your conclusion in part (a) by graphing f near x0 = -1 and using Zoom and Trace to estimate y-values on the graph as x approaches -1.
(c) Find the limit as x approaches -1 of (x^2 - 1) / (x - 1) algebraically.
(a) Complete the table given below.
Transcript text: Let $f(x)=\frac{x^{2}-1}{|x|-1}$ (a) Make tables of the values of $f$ at values of $x$ that approach $x_{0}=-1$ from above and below. Then estimate $\lim _{x \rightarrow-1} f(x)$. (b) Support your conclusion in part (a) by graphing f near $x_{0}=-1$ and using Zoom and Trace to estimate $y$-values on the graph as $x \rightarrow-1$. (c) Find $\lim _{x \rightarrow-1} \frac{x^{2}-1}{|x|-1}$ algebraically. (a) Complete the table given below.
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Solution

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Solution Steps

Step 1: Define the function \( f(x) \)

The function given is: \[ f(x) = \frac{x^2 - 1}{|x| - 1} \]

Step 2: Simplify the function

For \( x > 0 \): \[ f(x) = \frac{x^2 - 1}{x - 1} = \frac{(x - 1)(x + 1)}{x - 1} = x + 1 \]

For \( x < 0 \): \[ f(x) = \frac{x^2 - 1}{-x - 1} = \frac{(x - 1)(x + 1)}{-(x + 1)} = -(x - 1) = -x + 1 \]

Step 3: Evaluate the function as \( x \) approaches \(-1\) from above and below

For \( x \) approaching \(-1\) from above (\( x \to -1^+ \)): \[ f(x) = -x + 1 \] \[ f(-1^+) = -(-1) + 1 = 2 \]

For \( x \) approaching \(-1\) from below (\( x \to -1^- \)): \[ f(x) = -x + 1 \] \[ f(-1^-) = -(-1) + 1 = 2 \]

Step 4: Estimate the limit

Since both approaches give the same value: \[ \lim_{{x \to -1}} f(x) = 2 \]

Final Answer

The limit is: \[ \lim_{{x \to -1}} f(x) = 2 \]

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