Questions: 19. What is the mass for the car above? a) 2760 kg b) 9800 kg c) 918 kg d) 9000 kg 20. What is the net force? a) 1380 N right b) 918 N right c) 2760 N right d) 0 N 21. A rightward force of 302 N is applied to a 28.6-kg crate to accelerate it across the floor. The coefficient of friction between the crate and the floor is 0.750. Determine the acceleration of the crate. a) a=7.3 m / s^2 b) a =10.5 m / s^2 c) a=6.4 m / s^2 d) a=3.2 m / s^2 22. Suppose that a cart is accelerating at a rate of 3 m / s^2. If the net force is halved and the mass is tripled, then what is the new acceleration of the cart? a) 3 m / s^2 b) 0.5 m / s^2 c) 4.5 m / s^2 d) 2 m / s^2

19. What is the mass for the car above?
a) 2760 kg
b) 9800 kg
c) 918 kg
d) 9000 kg
20. What is the net force?
a) 1380 N right
b) 918 N right
c) 2760 N right
d) 0 N
21. A rightward force of 302 N is applied to a 28.6-kg crate to accelerate it across the floor. The coefficient of friction between the crate and the floor is 0.750. Determine the acceleration of the crate.
a) a=7.3 m / s^2
b) a =10.5 m / s^2
c) a=6.4 m / s^2
d) a=3.2 m / s^2
22. Suppose that a cart is accelerating at a rate of 3 m / s^2. If the net force is halved and the mass is tripled, then what is the new acceleration of the cart?
a) 3 m / s^2
b) 0.5 m / s^2
c) 4.5 m / s^2
d) 2 m / s^2

Transcript text: 19. What is the mass for the car above? a) 2760 kg b) 9800 kg c) 918 kg d) 9000 kg 20. What is the net force? a) 1380 N right b) 918 N right c) 2760 N right d) 0 N 21. A rightward force of 302 N is applied to a $28.6-\mathrm{kg}$ crate to accelerate it across the floor. The coefficient of friction between the crate and the floor is 0.750 . Determine the acceleration of the crate. a) $a=7.3 \mathrm{~m} / \mathrm{s} 2$ b) a $=10.5 \mathrm{~m} / \mathrm{s} 2$ c) $a=6.4 \mathrm{~m} / \mathrm{s} 2$ d) $a=3.2 \mathrm{~m} / \mathrm{s} 2$ 22. Suppose that a cart is accelerating at a rate of $3 \mathrm{~m} / \mathrm{s} 2$. If the net force is halved and the mass is tripled, then what is the new acceleration of the cart? a) $3 \mathrm{~m} / \mathrm{s} 2$ b) $0.5 \mathrm{~m} / \mathrm{s} 2$ c) $4.5 \mathrm{~m} / \mathrm{s} 2$ d) $2 \mathrm{~m} / \mathrm{s} 2$

Solution

Solution Steps

Step 1: Identify the given values and the formula needed

The problem provides the acceleration $ a = 1.50 \, \text{m/s}^2 $ and the net force $ \Sigma F = 9000 \, \text{N} $. We need to find the mass $ m $ of the car. The formula relating force, mass, and acceleration is Newton's second law: \[ \Sigma F = m \cdot a \]

Step 2: Rearrange the formula to solve for mass

Rearrange the formula to solve for $ m $: \[ m = \frac{\Sigma F}{a} \]

Step 3: Substitute the given values into the formula

Substitute the given values $ \Sigma F = 9000 \, \text{N} $ and $ a = 1.50 \, \text{m/s}^2 $ into the formula: \[ m = \frac{9000 \, \text{N}}{1.50 \, \text{m/s}^2} \]

Step 4: Calculate the mass

Perform the calculation: \[ m = \frac{9000}{1.50} = 6000 \, \text{kg} \]