Questions: Evaluate f(g(1)) and g(f(2)), if possible. If not type NA.
f(x) = x / (2 - x), g(x) = 4 - x^2
f(g(1)) =
g(f(2)) =
Transcript text: Evaluate $f(g(1))$ and $g(f(2))$, if possible. If not type NA.
\[
f(x)=\frac{x}{2-x}, g(x)=4-x^{2}
\]
$f(g(1))=$ $\square$
$g(f(2))=$ $\square$
Solution
Solution Steps
To solve the problem of evaluating \( f(g(1)) \) and \( g(f(2)) \), we need to follow these steps:
Evaluate \( g(1) \): Substitute \( x = 1 \) into the function \( g(x) = 4 - x^2 \) to find \( g(1) \).
Evaluate \( f(g(1)) \): Use the result from step 1 and substitute it into the function \( f(x) = \frac{x}{2-x} \).
Evaluate \( f(2) \): Substitute \( x = 2 \) into the function \( f(x) = \frac{x}{2-x} \) to find \( f(2) \).
Evaluate \( g(f(2)) \): Use the result from step 3 and substitute it into the function \( g(x) = 4 - x^2 \).
Step 1: Evaluate \( g(1) \)
First, we need to evaluate \( g(1) \) using the function \( g(x) = 4 - x^2 \).
\[
g(1) = 4 - (1)^2 = 4 - 1 = 3
\]
Step 2: Evaluate \( f(g(1)) \)
Now that we have \( g(1) = 3 \), we can evaluate \( f(g(1)) = f(3) \) using the function \( f(x) = \frac{x}{2-x} \).
\[
f(3) = \frac{3}{2-3} = \frac{3}{-1} = -3
\]
Step 3: Evaluate \( f(2) \)
Next, we need to evaluate \( f(2) \) using the function \( f(x) = \frac{x}{2-x} \).
\[
f(2) = \frac{2}{2-2} = \frac{2}{0}
\]
Since division by zero is undefined, \( f(2) \) is not defined.
Step 4: Evaluate \( g(f(2)) \)
Since \( f(2) \) is not defined, \( g(f(2)) \) is also not defined. Therefore, we write NA for \( g(f(2)) \).